anonymous
  • anonymous
Formulas for Q3? "For the last two parts assume I = 2A" Also, formulas for Q6 please :)
MIT 6.002 Circuits and Electronics, Spring 2007
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
q6 the formula 1-Vo* (R3-(B*R1*R3)+R1+R2+A*R2)/(R3-B*R1*R3)=VIN 2-i1=V0/(R3-B*R1*R3) 3- vo = vth but i don't know the RTH
anonymous
  • anonymous
Rth plzzzz
anonymous
  • anonymous
Thank you Sara! I'm still missing Rth formula, and the 2nd part of Q3 ones...

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anonymous
  • anonymous
When I=2 v1 is 1,32 and v2 is 0,66
anonymous
  • anonymous
Thank you zozi, but that seems to be wrong:c
anonymous
  • anonymous
what formulas did you use? My Resistances are 1ohm
anonymous
  • anonymous
just valculating v1, one 1 ohm and two serial resistors in paralel means a 0,66ohm resistor. From this U=I*R for v1 and for v0 its a half divider from two one ohm resistor...
benzo
  • benzo
sara do you mean I1= vin/(r3-b*r1*r3 vo=vin*(r3-(b*r1*r3)+r1+r2+a*r2)/(r3-b*r1*r3)
benzo
  • benzo
q6
anonymous
  • anonymous
Q6 Rth please Vin=18V, R1=1.5Ω, R2=3Ω, R3=4Ω, A=1.5 and B=0.5.
anonymous
  • anonymous
como vc fez o Q3, Joao?
anonymous
  • anonymous
eu achei aki as respostas para o meu
anonymous
  • anonymous
Thank you once again zozi, it was v0= 0.666 and v1=1.32, it was the other way around Also, for you Joao Vitor, RTH = 3.6
benzo
  • benzo
jones what the formula for q6
anonymous
  • anonymous
are you sure abt that, Jone133?
anonymous
  • anonymous
Yes, for I=2A on Q3 and for the values of JoaoMC on Q6
anonymous
  • anonymous
THANK YOU SOO MUCH!!
anonymous
  • anonymous
RTH= Vth / ISC Isc= Current on short circuit
benzo
  • benzo
I1 Vo Vth Rth
anonymous
  • anonymous
but how did you calculate the Rth ???
anonymous
  • anonymous
Finally 100% \o/
anonymous
  • anonymous
congrats! It's a great accomplishment, I hope I get 100% too on the final :D
benzo
  • benzo
formula please jones...
anonymous
  • anonymous
Hey Jone133.. my values are: 10A and -3A for v0 and 5A for v1 and v0
anonymous
  • anonymous
Dá uma força com o 6 aí, joao?? =D
anonymous
  • anonymous
I don't have formulas, sorry... I Only know that RTH = VTH / Isc and Isc is the current on short circuit. Zizo told me the values for Q3.
benzo
  • benzo
mc congrats q6 whats the formula
anonymous
  • anonymous
para os valores de JoaoMC, Vo, I and Vth are 1.8 The formulas are on the 1st answer
benzo
  • benzo
ok I1 and vo
anonymous
  • anonymous
also, vo = vth
anonymous
  • anonymous
Q6: Vin=18V, R1=1.5Ω, R2=3Ω, R3=4Ω, A=1.5 and B=0.5. 1.8 1.8 1.8 3.6
anonymous
  • anonymous
but still no formulas...
anonymous
  • anonymous
For Q3 v0= 0,66*I/2 but if its over +/- 2V the zener cuts it to +/-2V (found zizo's answer on another question)
anonymous
  • anonymous
Thank you Zozi!
anonymous
  • anonymous
and v1 is 0,66*I
benzo
  • benzo
JoãoVitorMC u is the mannn thank u
anonymous
  • anonymous
welcome :)
anonymous
  • anonymous
i will post soon a topic here about solve all the Question 3 and others that i complete understant.
anonymous
  • anonymous
Eu vi que teu Rth deu o dobro do teu Vth.. posso assumir isso pro meu, será? meu vth tá em 7.5
anonymous
  • anonymous
acho melhor não arriscar não
anonymous
  • anonymous
espera até amanha, deve aparecer mais soluções
anonymous
  • anonymous
agora q acabei aki, vou trabalhar em como encontrar as respostas e irei postar aki o mais rapido possivel
anonymous
  • anonymous
Q3: p1 : zener voltage sholud be less than the given current so vo=2V which is zener voltage Q3: P2 : I1=( 0.66 * I ) . . . also find I2 = (0.33 * I) .. . Vo= I2 Q3: P3 : (a) I1=( 0.66 * I ) . . . also find I2 = (0.33 * I) .. . Vo= I2 . . (b) v1 = I1
anonymous
  • anonymous
what is Isc in Q6
anonymous
  • anonymous
anonymous
  • anonymous
Rth help plzzz
anonymous
  • anonymous
if you assume I=2A then the current through the parallel resistor will be 1.3333 A ant V1 will be(1ohm*1.333) 1.333V the remaining current flows through the zener diode its resistance will be 1ohm so v0 will be 0.667v
anonymous
  • anonymous
anyone qno 4 part first equation????

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