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what is the residual for the equation 6.4+0.93x for x=60 and y=59
 one year ago
 one year ago
what is the residual for the equation 6.4+0.93x for x=60 and y=59
 one year ago
 one year ago

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CliffSedgeBest ResponseYou've already chosen the best response.0
The residual is the difference between the data point and what the predictor equation predicts. Compare y=59 to y=6.4_0.93(60).
 one year ago

swansborobaseball2310Best ResponseYou've already chosen the best response.0
So i get that the answer is 3.2, but would it be positive or negative
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
I think negative to show that the point is below the predictor line.
 one year ago

slaaibakBest ResponseYou've already chosen the best response.0
It would be negative. The E(error/residual) = Y (actual value)  y (predicted value/estimated value) so E(residual) = 59  [6.4 + .93(60)] = 3.2
 one year ago
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