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Consider the circuit of Question 3|dw:1351209851440:dw|
We have the Norton pattern in this question but it's better is we transform this into Thévenin, so let's do this:
Rth = R1 || R2
Vth = I*Rth
Let take this parameters as e.g. R1 = 1 ,R2 = 1
So Rth = 1 || 1 = 0.5
Assuming that I=8A, what is the value of the voltage vo (in Volts)?
Vth = 8*0.5 = 4, but now if we look at i-v relationship we saw that if the voltage is greatter or equal to 2, the voltage stay at 2 volts.
So Answers: 2v
Now assuming that I=−3A, what is the value of the voltage vo (in Volts)?
Vth = -3*0.5 = -1.5, but now we saw in i-v relationship that it behaves likes a resistor with resistence 1 ohm. Voltage Divider!
-1.5*1/(1+0.5) = -1v
So Answers: -1v
Finally, for the last two parts assume that I=3A
What is the value of the voltage vo (in Volts)?
Vth = 3*0.5 = 1.5, Voltage divider again!
1.5*1/(1+0.5) = 1v
So Answer: 1v
What is the value of the voltage v1 (in Volts)?
now use Node Method on the original circuit but notice that our nonlinear device Z acts like a resistor(1 ohm) when I = 3v.
(v1/R1) - I + v1/(R2+1) = 0
v1 = 2v
So Answers: 2v
good luck with that!