anonymous
  • anonymous
[Solved] Question 3 - Midterm
MIT 6.002 Circuits and Electronics, Spring 2007
schrodinger
  • schrodinger
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anonymous
  • anonymous
Consider the circuit of Question 3|dw:1351209851440:dw|
anonymous
  • anonymous
We have the Norton pattern in this question but it's better is we transform this into Thévenin, so let's do this: Rth = R1 || R2 Vth = I*Rth
anonymous
  • anonymous
Let take this parameters as e.g. R1 = 1 ,R2 = 1 So Rth = 1 || 1 = 0.5 Assuming that I=8A, what is the value of the voltage vo (in Volts)? Vth = 8*0.5 = 4, but now if we look at i-v relationship we saw that if the voltage is greatter or equal to 2, the voltage stay at 2 volts. So Answers: 2v Now assuming that I=−3A, what is the value of the voltage vo (in Volts)? Vth = -3*0.5 = -1.5, but now we saw in i-v relationship that it behaves likes a resistor with resistence 1 ohm. Voltage Divider! -1.5*1/(1+0.5) = -1v So Answers: -1v Finally, for the last two parts assume that I=3A What is the value of the voltage vo (in Volts)? Vth = 3*0.5 = 1.5, Voltage divider again! 1.5*1/(1+0.5) = 1v So Answer: 1v What is the value of the voltage v1 (in Volts)? now use Node Method on the original circuit but notice that our nonlinear device Z acts like a resistor(1 ohm) when I = 3v. (v1/R1) - I + v1/(R2+1) = 0 v1 = 2v So Answers: 2v good luck with that!

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anonymous
  • anonymous
Hello there, Victor and Sam, for the last part I have I=1A, what will be V1?
anonymous
  • anonymous
for last part, vo = 0.33 and v1=0.66
anonymous
  • anonymous
thanks 57 JoãoVitorMC
anonymous
  • anonymous
i don't get the correct answer. my data is I=9,-3, second 4
anonymous
  • anonymous
the last answer i get the same answer 2 v but its not working. my I=4
anonymous
  • anonymous
here wen for last 2 parts I=1 ans pls
anonymous
  • anonymous
Hi guys, Vitor and Sam, for the last part I have I=2A, what will be V1? could you please help me

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