3psilon
sinx + 2cosx = 0 where 0<=x<=2pi, what can x be equal to



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nightwill
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sinx=2cosx
sinx/cosx=2
tanx=2
Whatever x that fits tanx=2

3psilon
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so I did \[\tan^{1}(2)\] and I got 1.107 which isn't correct

3psilon
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@nightwill

nightwill
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x has to be between 0 and 2pi, so 1.107 won't work.

nightwill
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the answer should be pi+arctan(2) which is about 2.03444

3psilon
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Why did you add pi ?

3psilon
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I'm trying to refresh on trig

nightwill
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I added pi so that it fits in the domain. tan x has a period of pi, so tan x = tan (x+pi) Therefore,
\[\tan(tan^{1}2)=tan(\pi+tan^{1}2)\]