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3psilon
 2 years ago
sinx + 2cosx = 0 where 0<=x<=2pi, what can x be equal to
3psilon
 2 years ago
sinx + 2cosx = 0 where 0<=x<=2pi, what can x be equal to

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nightwill
 2 years ago
Best ResponseYou've already chosen the best response.1sinx=2cosx sinx/cosx=2 tanx=2 Whatever x that fits tanx=2

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0so I did \[\tan^{1}(2)\] and I got 1.107 which isn't correct

nightwill
 2 years ago
Best ResponseYou've already chosen the best response.1x has to be between 0 and 2pi, so 1.107 won't work.

nightwill
 2 years ago
Best ResponseYou've already chosen the best response.1the answer should be pi+arctan(2) which is about 2.03444

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0I'm trying to refresh on trig

nightwill
 2 years ago
Best ResponseYou've already chosen the best response.1I added pi so that it fits in the domain. tan x has a period of pi, so tan x = tan (x+pi) Therefore, \[\tan(tan^{1}2)=tan(\pi+tan^{1}2)\]
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