rebecca1233
Part a.) Find the slope of the line that contains the points, (1, 2) and (2, 5).
Part b.) Using the slope that you found in part a and one of the given points, write the equation of the line. Please write your final answer in slope-intercept form.
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AriPotta
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do you know the slope formula?
rebecca1233
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sorta.. i forgot
AriPotta
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AriPotta
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what would the equation look like after you substitute the x's and y's?
rebecca1233
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2-5 / 2-1
AriPotta
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(2-5)/(1-2)
when you decide which coordinate pair will be "1" and "2" you gotta keep it like that
AriPotta
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so what's our slope?
rebecca1233
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idk ? im confused now
AriPotta
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what's 2 - 5?
rebecca1233
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-3
AriPotta
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and what's 1 - 2?
rebecca1233
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-1
AriPotta
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right, so what's -3/-1?
rebecca1233
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3
AriPotta
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exactly, so our slope is 3
AriPotta
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do you understand how we got that?
rebecca1233
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sorta can u just explain it in simplier terms
AriPotta
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|dw:1351215308811:dw|
AriPotta
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|dw:1351215523686:dw|
rebecca1233
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okay so part a : is slope is 3 and part b is ?
AriPotta
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do you know what point-slope form is?
AriPotta
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because you have to put the information into point-slope form first before you can get it into slope-intercept form
rebecca1233
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YES. im just confused on now part b
rebecca1233
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y = 3x and what for slope form
AriPotta
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what? point-slope form is y - y1 = m(x - x1)
rebecca1233
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(2-5)/(1-2)
AriPotta
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you haven't done part b yet
AriPotta
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if we use the first ordered pair for our equation, we know that y1 is 2, x1 is 1, and m is 3. so y - 2 = 3(x - 1)
AriPotta
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do you know how to change that into slope-intercept form?
rebecca1233
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no
rebecca1233
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y = 3x-1?
AriPotta
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that's right :D
rebecca1233
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thanks . i have a few more questions i need help with i would like help with them