anonymous
  • anonymous
If a car moving at 72.0 takes 300 to stop with uniform acceleration after its brakes are applied, how far will it take to stop under the same conditions if its initial velocity is 36.0 ?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
i got it wrong
anonymous
  • anonymous
These are my choices 15.0 37.5 75.0 150
3psilon
  • 3psilon
But it isn't 150?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
no i got it wrong
anonymous
  • anonymous
first, you need to find out how much acceleration (but slowing down, not going faster, so it will be negative) the car has. do this by using the equation vf^2 = vi^2 + 2ax. substitute in what you already know to find the acceleration. vf=0, vi=72, x=300. then use the same equation after solving for "a" to find x. set vf = 0, vi = 36, a = "a" from previous, and solve for x
anonymous
  • anonymous
hint: a = -8.64 from solving the first equation. put it into the second equation to get x = 75
anonymous
  • anonymous
ok thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.