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Grazes

  • 3 years ago

Solve.

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  1. Grazes
    • 3 years ago
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    |dw:1351218302693:dw|

  2. Freak7820
    • 3 years ago
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    factorise? x^2(x^2 -2) - 7(x^2 -2) = 0... (x^2-7) (x^2-2) =0.. then solve.

  3. freewilly922
    • 3 years ago
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    can you solve \[u^2 -9u+14=0\] ? then say \[u=x^2\]

  4. freewilly922
    • 3 years ago
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    \[u=x^2\] so \[u^2-9u+14\] \[(u-7)(u-2)=0\] u=7,2 so \[x^2=7; x= \pm \sqrt{7} \;and\; x^2=2; x=\pm \sqrt{2}\]

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