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wio Group TitleBest ResponseYou've already chosen the best response.0
So this is a 3D plane, isn't it?
 2 years ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
eek 3d. vectors all over again
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Remember that when x, y are 0 then z is 6, when x, z are 0 then y is 6 etc
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
So plot the points on the intercepts first.
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
it has to be a plane, so it shouldn't be hard to make out the shape from there.
 2 years ago

bri4life14 Group TitleBest ResponseYou've already chosen the best response.0
how would this look
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Also, it has a normal vector of <1, 1, 1> so it is perpendicular to that vector.
 2 years ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
You need the littleknown but very useful Intercept Form. Divide by 6. x/6 + y/6 + z/6 = 1 This is the Intercept Form. It says: xintercept (6,0,0) yintercept (0,6,0) z=intercept (0,0,6)
 2 years ago
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