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wio Group TitleBest ResponseYou've already chosen the best response.0
So this is a 3D plane, isn't it?
 one year ago

NotTim Group TitleBest ResponseYou've already chosen the best response.0
eek 3d. vectors all over again
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Remember that when x, y are 0 then z is 6, when x, z are 0 then y is 6 etc
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
So plot the points on the intercepts first.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
it has to be a plane, so it shouldn't be hard to make out the shape from there.
 one year ago

bri4life14 Group TitleBest ResponseYou've already chosen the best response.0
how would this look
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Also, it has a normal vector of <1, 1, 1> so it is perpendicular to that vector.
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
You need the littleknown but very useful Intercept Form. Divide by 6. x/6 + y/6 + z/6 = 1 This is the Intercept Form. It says: xintercept (6,0,0) yintercept (0,6,0) z=intercept (0,0,6)
 one year ago
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