anonymous
  • anonymous
graph x+y+Z=6
Algebra
schrodinger
  • schrodinger
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anonymous
  • anonymous
So this is a 3D plane, isn't it?
anonymous
  • anonymous
yes
NotTim
  • NotTim
eek 3-d. vectors all over again

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anonymous
  • anonymous
Remember that when x, y are 0 then z is 6, when x, z are 0 then y is 6 etc
anonymous
  • anonymous
So plot the points on the intercepts first.
anonymous
  • anonymous
it has to be a plane, so it shouldn't be hard to make out the shape from there.
anonymous
  • anonymous
how would this look
anonymous
  • anonymous
Also, it has a normal vector of <1, 1, 1> so it is perpendicular to that vector.
tkhunny
  • tkhunny
You need the little-known but very useful Intercept Form. Divide by 6. x/6 + y/6 + z/6 = 1 This is the Intercept Form. It says: x-intercept (6,0,0) y-intercept (0,6,0) z=intercept (0,0,6)

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