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bri4life14

graph x+y+Z=6

  • one year ago
  • one year ago

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  1. wio
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    So this is a 3D plane, isn't it?

    • one year ago
  2. bri4life14
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    yes

    • one year ago
  3. NotTim
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    eek 3-d. vectors all over again

    • one year ago
  4. wio
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    Remember that when x, y are 0 then z is 6, when x, z are 0 then y is 6 etc

    • one year ago
  5. wio
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    So plot the points on the intercepts first.

    • one year ago
  6. wio
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    it has to be a plane, so it shouldn't be hard to make out the shape from there.

    • one year ago
  7. bri4life14
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    how would this look

    • one year ago
  8. wio
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    Also, it has a normal vector of <1, 1, 1> so it is perpendicular to that vector.

    • one year ago
  9. tkhunny
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    You need the little-known but very useful Intercept Form. Divide by 6. x/6 + y/6 + z/6 = 1 This is the Intercept Form. It says: x-intercept (6,0,0) y-intercept (0,6,0) z=intercept (0,0,6)

    • one year ago
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