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jennilalala

  • 2 years ago

Calculate the energy in J of 0.32 moles of photons whose frequency is 2.6 x 10^15 ?

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  1. SheldonEinstein
    • 2 years ago
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    You must know the formula for calculating the energy... in this situation. Do you know the formula?

  2. aaronq
    • 2 years ago
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    E=hv h is planks constant v= frequency this gives you the energy of 1 photon so multiply this by the amount of photons you have: amount of photons = avogadros constant x number of moles

  3. SheldonEinstein
    • 2 years ago
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    that v is actually "new (pronounced as new)"

  4. SheldonEinstein
    • 2 years ago
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    So @jennilalala with the help of : E = hv formula, can you find the energy by putting the values given ?

  5. SheldonEinstein
    • 2 years ago
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    "v" --> \(\large{\color{blue}{\nu}}\) .... right @aaronq ?

  6. jennilalala
    • 2 years ago
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    I am back sorry ahaah. yes i know the formulas. i just dont know what to do if it says ".32 moles of photon.."

  7. SheldonEinstein
    • 2 years ago
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    Do you the planck's constant ?

  8. jennilalala
    • 2 years ago
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    6.626x10^23 ?? not by heart...yet...

  9. aaronq
    • 2 years ago
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    haha yep, v= "new"

  10. jennilalala
    • 2 years ago
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    10^-34

  11. SheldonEinstein
    • 2 years ago
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    OK so it is \[\large { h = 6.626 \times 10^{-34} m^{-1}}\]

  12. SheldonEinstein
    • 2 years ago
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    oh wait it is m^2 kg/s

  13. SheldonEinstein
    • 2 years ago
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    So right, now solve this : \[\large{E = 6.626 \times 10^{-34} \times 2.6 \times 10^{15}}\] What do you get?

  14. jennilalala
    • 2 years ago
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    1.73x10^-18

  15. SheldonEinstein
    • 2 years ago
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    My calculator says it as : \(\large{\color{blue}{ 17.2276 * 10^{-19}}}\) that is 1.72276 * 10^{-18}

  16. SheldonEinstein
    • 2 years ago
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    OK so now .. this is the energy for \(1\) photon ... now we to calculate for 0.32 moles of photons.

  17. SheldonEinstein
    • 2 years ago
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    See ... no. of photons = Avogadros's constant * no. of moles of photons...

  18. SheldonEinstein
    • 2 years ago
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    You know avogadro's constant?

  19. jennilalala
    • 2 years ago
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    6.022x10^23

  20. SheldonEinstein
    • 2 years ago
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    Good! So now, solve this one : \[\large{\color{red}{\mathbb{No. of Photons}} = \color{blue}{6.022 * {10}^{23}} \times \color{green}{0.32}}\]

  21. jennilalala
    • 2 years ago
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    1.93x10^23

  22. jennilalala
    • 2 years ago
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    then i multiply the two calculations?

  23. SheldonEinstein
    • 2 years ago
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    Correct! So this is your No. of photons. Now multiply this result with "1.73 * 10^{-18} "

  24. jennilalala
    • 2 years ago
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    3.3x10^-5

  25. SheldonEinstein
    • 2 years ago
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    Right!

  26. jennilalala
    • 2 years ago
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    not negative typo lol

  27. SheldonEinstein
    • 2 years ago
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    No problem.

  28. SheldonEinstein
    • 2 years ago
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    So finally you have your correct way, I hope you got it ?

  29. jennilalala
    • 2 years ago
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    Yes thank you so much!

  30. SheldonEinstein
    • 2 years ago
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    You're welcome @jennilalala . keep up the good work.

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