anonymous
  • anonymous
Calculate the energy in J of 0.32 moles of photons whose frequency is 2.6 x 10^15 ?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
You must know the formula for calculating the energy... in this situation. Do you know the formula?
aaronq
  • aaronq
E=hv h is planks constant v= frequency this gives you the energy of 1 photon so multiply this by the amount of photons you have: amount of photons = avogadros constant x number of moles
anonymous
  • anonymous
that v is actually "new (pronounced as new)"

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anonymous
  • anonymous
So @jennilalala with the help of : E = hv formula, can you find the energy by putting the values given ?
anonymous
  • anonymous
"v" --> \(\large{\color{blue}{\nu}}\) .... right @aaronq ?
anonymous
  • anonymous
I am back sorry ahaah. yes i know the formulas. i just dont know what to do if it says ".32 moles of photon.."
anonymous
  • anonymous
Do you the planck's constant ?
anonymous
  • anonymous
6.626x10^23 ?? not by heart...yet...
aaronq
  • aaronq
haha yep, v= "new"
anonymous
  • anonymous
10^-34
anonymous
  • anonymous
OK so it is \[\large { h = 6.626 \times 10^{-34} m^{-1}}\]
anonymous
  • anonymous
oh wait it is m^2 kg/s
anonymous
  • anonymous
So right, now solve this : \[\large{E = 6.626 \times 10^{-34} \times 2.6 \times 10^{15}}\] What do you get?
anonymous
  • anonymous
1.73x10^-18
anonymous
  • anonymous
My calculator says it as : \(\large{\color{blue}{ 17.2276 * 10^{-19}}}\) that is 1.72276 * 10^{-18}
anonymous
  • anonymous
OK so now .. this is the energy for \(1\) photon ... now we to calculate for 0.32 moles of photons.
anonymous
  • anonymous
See ... no. of photons = Avogadros's constant * no. of moles of photons...
anonymous
  • anonymous
You know avogadro's constant?
anonymous
  • anonymous
6.022x10^23
anonymous
  • anonymous
Good! So now, solve this one : \[\large{\color{red}{\mathbb{No. of Photons}} = \color{blue}{6.022 * {10}^{23}} \times \color{green}{0.32}}\]
anonymous
  • anonymous
1.93x10^23
anonymous
  • anonymous
then i multiply the two calculations?
anonymous
  • anonymous
Correct! So this is your No. of photons. Now multiply this result with "1.73 * 10^{-18} "
anonymous
  • anonymous
3.3x10^-5
anonymous
  • anonymous
Right!
anonymous
  • anonymous
not negative typo lol
anonymous
  • anonymous
No problem.
anonymous
  • anonymous
So finally you have your correct way, I hope you got it ?
anonymous
  • anonymous
Yes thank you so much!
anonymous
  • anonymous
You're welcome @jennilalala . keep up the good work.

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