Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jennilalala

Calculate the energy in J of 0.32 moles of photons whose frequency is 2.6 x 10^15 ?

  • one year ago
  • one year ago

  • This Question is Closed
  1. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    You must know the formula for calculating the energy... in this situation. Do you know the formula?

    • one year ago
  2. aaronq
    Best Response
    You've already chosen the best response.
    Medals 1

    E=hv h is planks constant v= frequency this gives you the energy of 1 photon so multiply this by the amount of photons you have: amount of photons = avogadros constant x number of moles

    • one year ago
  3. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    that v is actually "new (pronounced as new)"

    • one year ago
  4. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    So @jennilalala with the help of : E = hv formula, can you find the energy by putting the values given ?

    • one year ago
  5. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    "v" --> \(\large{\color{blue}{\nu}}\) .... right @aaronq ?

    • one year ago
  6. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    I am back sorry ahaah. yes i know the formulas. i just dont know what to do if it says ".32 moles of photon.."

    • one year ago
  7. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    Do you the planck's constant ?

    • one year ago
  8. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    6.626x10^23 ?? not by heart...yet...

    • one year ago
  9. aaronq
    Best Response
    You've already chosen the best response.
    Medals 1

    haha yep, v= "new"

    • one year ago
  10. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    10^-34

    • one year ago
  11. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    OK so it is \[\large { h = 6.626 \times 10^{-34} m^{-1}}\]

    • one year ago
  12. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    oh wait it is m^2 kg/s

    • one year ago
  13. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    So right, now solve this : \[\large{E = 6.626 \times 10^{-34} \times 2.6 \times 10^{15}}\] What do you get?

    • one year ago
  14. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    1.73x10^-18

    • one year ago
  15. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    My calculator says it as : \(\large{\color{blue}{ 17.2276 * 10^{-19}}}\) that is 1.72276 * 10^{-18}

    • one year ago
  16. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    OK so now .. this is the energy for \(1\) photon ... now we to calculate for 0.32 moles of photons.

    • one year ago
  17. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    See ... no. of photons = Avogadros's constant * no. of moles of photons...

    • one year ago
  18. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    You know avogadro's constant?

    • one year ago
  19. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    6.022x10^23

    • one year ago
  20. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    Good! So now, solve this one : \[\large{\color{red}{\mathbb{No. of Photons}} = \color{blue}{6.022 * {10}^{23}} \times \color{green}{0.32}}\]

    • one year ago
  21. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    1.93x10^23

    • one year ago
  22. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    then i multiply the two calculations?

    • one year ago
  23. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    Correct! So this is your No. of photons. Now multiply this result with "1.73 * 10^{-18} "

    • one year ago
  24. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    3.3x10^-5

    • one year ago
  25. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    Right!

    • one year ago
  26. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    not negative typo lol

    • one year ago
  27. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    No problem.

    • one year ago
  28. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    So finally you have your correct way, I hope you got it ?

    • one year ago
  29. jennilalala
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes thank you so much!

    • one year ago
  30. SheldonEinstein
    Best Response
    You've already chosen the best response.
    Medals 2

    You're welcome @jennilalala . keep up the good work.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.