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You must know the formula for calculating the energy... in this situation.
Do you know the formula?

that v is actually "new (pronounced as new)"

Do you the planck's constant ?

6.626x10^23 ?? not by heart...yet...

haha yep, v= "new"

10^-34

OK so it is \[\large { h = 6.626 \times 10^{-34} m^{-1}}\]

oh wait it is m^2 kg/s

1.73x10^-18

My calculator says it as : \(\large{\color{blue}{ 17.2276 * 10^{-19}}}\) that is 1.72276 * 10^{-18}

OK so now .. this is the energy for \(1\) photon ... now we to calculate for 0.32 moles of photons.

See ... no. of photons = Avogadros's constant * no. of moles of photons...

You know avogadro's constant?

6.022x10^23

1.93x10^23

then i multiply the two calculations?

Correct! So this is your No. of photons.
Now multiply this result with "1.73 * 10^{-18} "

3.3x10^-5

Right!

not negative typo lol

No problem.

So finally you have your correct way, I hope you got it ?

Yes thank you so much!

You're welcome @jennilalala . keep up the good work.