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kavi11

  • 2 years ago

Rth helpp....Vin =27V , R 1 =5Ω , R 2 =7Ω , R 3 =12Ω , A=6 and B=0.1 .

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  1. aditya16
    • 2 years ago
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    put Isc=0.25 in rth=vth/Isc

  2. Logan2
    • 2 years ago
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    it's just missing this one to me too .. Does anybody help me too ? Rth ... Vin=15V, R1=0.5Ω, R2=1.5Ω, R3=5Ω, A=2 and B=1.5.

  3. aditya16
    • 2 years ago
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    cn u post formula of power in q2

  4. Logan2
    • 2 years ago
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    Q2 is the same of HW3.. yeah.. for sure .. one minute !

  5. Logan2
    • 2 years ago
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    EXPLANATION: VS=5.0 VOH=4.5 VIH=4.0 VIL=1.5 VOL=1.0 The low noise margin is defined as VIL−VOL. For this problem, it is 0.5V. As an example, if an inverter outputs a valid voltage signal of 1.0V (VOL) to another inverter, then that signal can rise by 0.5V all the way to VIL, before it becomes an invalid logical 0 input to the second inverter. The high noise margin is defined as VOH−VIH. For this problem, it is 0.5V. Again, if an inverter outputs a valid voltage signal of 4.5V(VOH) to another inverter, then that signal can fall by 0.5V, all the way to VIH before it becomes an invalid logical 1 input to the second inverter. The width of the forbidden region is defined as VIH−VIL. For this problem, it is 2.5V. Valid inputs to our logic family are not allowed to fall between VIH and VIL. When VGS for the MOSFET is below VT, the MOSFET behaves like an open circuit, and iDS=0. That means no voltage drops over RPUI and the output voltage of our inverter is VS, so this case is fine with out static discipline, since the output voltage is above VOH. For VGS≥VT, the MOSFET is on and behaves like a resistor with resistance RON with our model. To find RPUI: VOL=VS(RON)RON+RPUI 1=5(5000.0)(5000.0+RPUI)→RPUI=20000.0Ω Similar to the inverter case, when either MOSFET is off, no current can flow through the pullup resistor because the MOSFETs and pullup resistor are in series. So VOUT for the NAND gate is simply VS when either MOSFET is off. When both MOSFETs are on, they behave like resistors with resistance RON. The two MOSFETs are in series, so we calculate: To find RPUA: VOL=VS(2RON)2RON+RPUA 1=5(10000.0)(10000.0+RPUA)→RPUA=40000.0Ω When both MOSFETs are off, VOUT for the NOR gate is simply VS because no current can flow through either MOSFET or RPUO. When one MOSFET is on, VOUT is: VS⋅(0.5)RON(0.5)RON+RPUO because the MOSFETs are in parallel with each other. For the cases with one MOSFET on or both MOSFETs on, VOUT must be at least as small as VOL. For the case with one MOSFET on, RPUO must be at least 20000.0 Ω. For the case with both MOSFETs on, RPUO must be at least 10000.0 Ω. So for our NOR gate to satisfy the static discipline, RPUO must be at least 20000.0 Ω. When the MOSFET in the inverter is off, no power is consumed because no current can flow as the MOSFET behaves like an open circuit. When it is on, VS must drop over RPUI and RON, so the power consumed is: (VS)2RPUI+RON Power consumed by inverter: 25V5000.0+20000.0Ω=0.001W When either MOSFET is off, no current flows through the MOSFETs or RPUA, so there is no power consumed. When both MOSFETs are on, VS must drop over RPUA and 2RON because the MOSFETs are in series with each other. The power consumed in this case is: (VS)2RPUA+2RON Power consumed by NAND: 25V2⋅5000.0+40000.0Ω=0.0005W When both MOSFETs are off, no curernt can flow, so no power is consumed. When one MOSFET is on, VS must drop over RPUO and RON, so the power consumed is: (VS)2RPUO+RON When both MOSFETs are on, VS must drop over RPUO and 12 RON because the MOSFETs are in parallel, so the power consumed is: (VS)2RPUO+0.5(RON) The maximum power is consumed by the NOR gate in the latter case: 25V(5000.0∥5000.0)+20000.0Ω=0.001111W

  6. aditya16
    • 2 years ago
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    i forget the formula..

  7. Logan2
    • 2 years ago
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    VIL−VOL

  8. Logan2
    • 2 years ago
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    the first one

  9. aditya16
    • 2 years ago
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    thnx dude

  10. Logan2
    • 2 years ago
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    The high noise margin is defined as VOH−VIH

  11. Logan2
    • 2 years ago
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    The width of the forbidden region is defined as VIH−VIL

  12. aditya16
    • 2 years ago
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    can u plss solve this for me.. may b some calculation error vT=2, Ron =18000

  13. Logan2
    • 2 years ago
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    To find RPUI: VOL=VS(RON)/RON+RPUI

  14. ThundaCheese
    • 2 years ago
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    Rth formula for Q6?

  15. Logan2
    • 2 years ago
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    yeah.. I'll solve .. one minute .. I don't know yet Thunda.. I am really want to know too

  16. Logan2
    • 2 years ago
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    I really want *

  17. Logan2
    • 2 years ago
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    give me the values Vs etc etc ...

  18. aditya16
    • 2 years ago
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    hey put Isc =0.75 in formula rth=vth/Isc

  19. aditya16
    • 2 years ago
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    Vs=5v

  20. aditya16
    • 2 years ago
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    what nurali?

  21. ThundaCheese
    • 2 years ago
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    Thanks a bunch!!

  22. Logan2
    • 2 years ago
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    and what about Vol ? what's value yours ?

  23. Nurali
    • 2 years ago
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    reply aditya

  24. aditya16
    • 2 years ago
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    1 min

  25. aditya16
    • 2 years ago
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    short circuit that circuit then calculate the current in that circuit., now that current I=Isc+B*vb

  26. aditya16
    • 2 years ago
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    Vol=1V

  27. Logan2
    • 2 years ago
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    try this value 72000 ... because Vol=Vs*Ron/Ron*Rput then we have 1=5*18000/18000+Rput to be 1= 1 the variable Rput is 72000

  28. aditya16
    • 2 years ago
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    hey for power of nand the formula is : Vs^2/(Rpul+2*Ron) but i got wrong answer

  29. Logan2
    • 2 years ago
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    I'll help you.. 1 m

  30. Logan2
    • 2 years ago
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    maybe your Rpua is not correct.. give me this value.. Rpua

  31. aditya16
    • 2 years ago
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    hey i got.. thanx..:)

  32. Logan2
    • 2 years ago
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    ooh no problem.. did you get entire Q2 ?

  33. aditya16
    • 2 years ago
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    yup

  34. Logan2
    • 2 years ago
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    great !!

  35. Logan2
    • 2 years ago
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    can you help with Rth in Q6 ?

  36. Logan2
    • 2 years ago
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    Isc=0,75.. is it this value that you said ?

  37. aditya16
    • 2 years ago
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    yupp.. 0.75

  38. aditya16
    • 2 years ago
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    what is your vth?

  39. Logan2
    • 2 years ago
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    it's 3

  40. Logan2
    • 2 years ago
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    vout= vth ... it's 3

  41. aditya16
    • 2 years ago
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    rth=4

  42. Logan2
    • 2 years ago
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    it's my last chance.. it's final check ..

  43. Logan2
    • 2 years ago
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    is it really 4 ?

  44. aditya16
    • 2 years ago
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    so wait.. 1st i recheck

  45. Logan2
    • 2 years ago
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    thank you so much

  46. Logan2
    • 2 years ago
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    look my values are Vin=15V, R1=0.5Ω, R2=1.5Ω, R3=5Ω, A=2 and B=1.5.

  47. aditya16
    • 2 years ago
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    rth=4

  48. aditya16
    • 2 years ago
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    get correct?

  49. Logan2
    • 2 years ago
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    yeah... THANK YOU SO MUCH !

  50. akash97
    • 2 years ago
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    @kavi11: ur ans 1) 0.45 2)2.7 3)2.7 4)10.8

  51. xmark
    • 2 years ago
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    @akash97 : how do u get that ? can you post the formula ?

  52. akash97
    • 2 years ago
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    @xmark : I got using analysis der is no kind of formula dar I use directly

  53. Qaisersatti
    • 2 years ago
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    Vin 27 v R1 5 ohm r2 = 7 Ohms R3 12 Ohms A=6 and B=0.1 QNO6 answers please please please ?

  54. Qaisersatti
    • 2 years ago
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    time is running out for my friend....

  55. Logan2
    • 2 years ago
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    question 6 1)Vo* (R3-(B*R1*R3)+R1+R2+A*R2)/(R3-B*R1*R3)=VIN 2)i1=V0/(R3-B*R1*R3) 3)vo = vth 4)Rth=Vth/Isc I=Isc+B*vb

  56. charansg
    • 2 years ago
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    http://openstudy.com/study#/updates/508b8bc0e4b077c2ef2e9093

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