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Rth helpp....Vin =27V , R 1 =5Ω , R 2 =7Ω , R 3 =12Ω , A=6 and B=0.1 .
 one year ago
 one year ago
Rth helpp....Vin =27V , R 1 =5Ω , R 2 =7Ω , R 3 =12Ω , A=6 and B=0.1 .
 one year ago
 one year ago

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aditya16Best ResponseYou've already chosen the best response.3
put Isc=0.25 in rth=vth/Isc
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
it's just missing this one to me too .. Does anybody help me too ? Rth ... Vin=15V, R1=0.5Ω, R2=1.5Ω, R3=5Ω, A=2 and B=1.5.
 one year ago

aditya16Best ResponseYou've already chosen the best response.3
cn u post formula of power in q2
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
Q2 is the same of HW3.. yeah.. for sure .. one minute !
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
EXPLANATION: VS=5.0 VOH=4.5 VIH=4.0 VIL=1.5 VOL=1.0 The low noise margin is defined as VIL−VOL. For this problem, it is 0.5V. As an example, if an inverter outputs a valid voltage signal of 1.0V (VOL) to another inverter, then that signal can rise by 0.5V all the way to VIL, before it becomes an invalid logical 0 input to the second inverter. The high noise margin is defined as VOH−VIH. For this problem, it is 0.5V. Again, if an inverter outputs a valid voltage signal of 4.5V(VOH) to another inverter, then that signal can fall by 0.5V, all the way to VIH before it becomes an invalid logical 1 input to the second inverter. The width of the forbidden region is defined as VIH−VIL. For this problem, it is 2.5V. Valid inputs to our logic family are not allowed to fall between VIH and VIL. When VGS for the MOSFET is below VT, the MOSFET behaves like an open circuit, and iDS=0. That means no voltage drops over RPUI and the output voltage of our inverter is VS, so this case is fine with out static discipline, since the output voltage is above VOH. For VGS≥VT, the MOSFET is on and behaves like a resistor with resistance RON with our model. To find RPUI: VOL=VS(RON)RON+RPUI 1=5(5000.0)(5000.0+RPUI)→RPUI=20000.0Ω Similar to the inverter case, when either MOSFET is off, no current can flow through the pullup resistor because the MOSFETs and pullup resistor are in series. So VOUT for the NAND gate is simply VS when either MOSFET is off. When both MOSFETs are on, they behave like resistors with resistance RON. The two MOSFETs are in series, so we calculate: To find RPUA: VOL=VS(2RON)2RON+RPUA 1=5(10000.0)(10000.0+RPUA)→RPUA=40000.0Ω When both MOSFETs are off, VOUT for the NOR gate is simply VS because no current can flow through either MOSFET or RPUO. When one MOSFET is on, VOUT is: VS⋅(0.5)RON(0.5)RON+RPUO because the MOSFETs are in parallel with each other. For the cases with one MOSFET on or both MOSFETs on, VOUT must be at least as small as VOL. For the case with one MOSFET on, RPUO must be at least 20000.0 Ω. For the case with both MOSFETs on, RPUO must be at least 10000.0 Ω. So for our NOR gate to satisfy the static discipline, RPUO must be at least 20000.0 Ω. When the MOSFET in the inverter is off, no power is consumed because no current can flow as the MOSFET behaves like an open circuit. When it is on, VS must drop over RPUI and RON, so the power consumed is: (VS)2RPUI+RON Power consumed by inverter: 25V5000.0+20000.0Ω=0.001W When either MOSFET is off, no current flows through the MOSFETs or RPUA, so there is no power consumed. When both MOSFETs are on, VS must drop over RPUA and 2RON because the MOSFETs are in series with each other. The power consumed in this case is: (VS)2RPUA+2RON Power consumed by NAND: 25V2⋅5000.0+40000.0Ω=0.0005W When both MOSFETs are off, no curernt can flow, so no power is consumed. When one MOSFET is on, VS must drop over RPUO and RON, so the power consumed is: (VS)2RPUO+RON When both MOSFETs are on, VS must drop over RPUO and 12 RON because the MOSFETs are in parallel, so the power consumed is: (VS)2RPUO+0.5(RON) The maximum power is consumed by the NOR gate in the latter case: 25V(5000.0∥5000.0)+20000.0Ω=0.001111W
 one year ago

aditya16Best ResponseYou've already chosen the best response.3
i forget the formula..
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
The high noise margin is defined as VOH−VIH
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
The width of the forbidden region is defined as VIH−VIL
 one year ago

aditya16Best ResponseYou've already chosen the best response.3
can u plss solve this for me.. may b some calculation error vT=2, Ron =18000
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
To find RPUI: VOL=VS(RON)/RON+RPUI
 one year ago

ThundaCheeseBest ResponseYou've already chosen the best response.0
Rth formula for Q6?
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
yeah.. I'll solve .. one minute .. I don't know yet Thunda.. I am really want to know too
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
give me the values Vs etc etc ...
 one year ago

aditya16Best ResponseYou've already chosen the best response.3
hey put Isc =0.75 in formula rth=vth/Isc
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
and what about Vol ? what's value yours ?
 one year ago

aditya16Best ResponseYou've already chosen the best response.3
short circuit that circuit then calculate the current in that circuit., now that current I=Isc+B*vb
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
try this value 72000 ... because Vol=Vs*Ron/Ron*Rput then we have 1=5*18000/18000+Rput to be 1= 1 the variable Rput is 72000
 one year ago

aditya16Best ResponseYou've already chosen the best response.3
hey for power of nand the formula is : Vs^2/(Rpul+2*Ron) but i got wrong answer
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
maybe your Rpua is not correct.. give me this value.. Rpua
 one year ago

aditya16Best ResponseYou've already chosen the best response.3
hey i got.. thanx..:)
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
ooh no problem.. did you get entire Q2 ?
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
can you help with Rth in Q6 ?
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
Isc=0,75.. is it this value that you said ?
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
it's my last chance.. it's final check ..
 one year ago

aditya16Best ResponseYou've already chosen the best response.3
so wait.. 1st i recheck
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
look my values are Vin=15V, R1=0.5Ω, R2=1.5Ω, R3=5Ω, A=2 and B=1.5.
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
yeah... THANK YOU SO MUCH !
 one year ago

akash97Best ResponseYou've already chosen the best response.0
@kavi11: ur ans 1) 0.45 2)2.7 3)2.7 4)10.8
 one year ago

xmarkBest ResponseYou've already chosen the best response.0
@akash97 : how do u get that ? can you post the formula ?
 one year ago

akash97Best ResponseYou've already chosen the best response.0
@xmark : I got using analysis der is no kind of formula dar I use directly
 one year ago

QaisersattiBest ResponseYou've already chosen the best response.0
Vin 27 v R1 5 ohm r2 = 7 Ohms R3 12 Ohms A=6 and B=0.1 QNO6 answers please please please ?
 one year ago

QaisersattiBest ResponseYou've already chosen the best response.0
time is running out for my friend....
 one year ago

Logan2Best ResponseYou've already chosen the best response.0
question 6 1)Vo* (R3(B*R1*R3)+R1+R2+A*R2)/(R3B*R1*R3)=VIN 2)i1=V0/(R3B*R1*R3) 3)vo = vth 4)Rth=Vth/Isc I=Isc+B*vb
 one year ago

charansgBest ResponseYou've already chosen the best response.0
http://openstudy.com/study#/updates/508b8bc0e4b077c2ef2e9093
 one year ago
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