Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
kavi11
Group Title
Rth helpp....Vin =27V , R 1 =5Ω , R 2 =7Ω , R 3 =12Ω , A=6 and B=0.1 .
 2 years ago
 2 years ago
kavi11 Group Title
Rth helpp....Vin =27V , R 1 =5Ω , R 2 =7Ω , R 3 =12Ω , A=6 and B=0.1 .
 2 years ago
 2 years ago

This Question is Closed

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
put Isc=0.25 in rth=vth/Isc
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
it's just missing this one to me too .. Does anybody help me too ? Rth ... Vin=15V, R1=0.5Ω, R2=1.5Ω, R3=5Ω, A=2 and B=1.5.
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
cn u post formula of power in q2
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
Q2 is the same of HW3.. yeah.. for sure .. one minute !
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
EXPLANATION: VS=5.0 VOH=4.5 VIH=4.0 VIL=1.5 VOL=1.0 The low noise margin is defined as VIL−VOL. For this problem, it is 0.5V. As an example, if an inverter outputs a valid voltage signal of 1.0V (VOL) to another inverter, then that signal can rise by 0.5V all the way to VIL, before it becomes an invalid logical 0 input to the second inverter. The high noise margin is defined as VOH−VIH. For this problem, it is 0.5V. Again, if an inverter outputs a valid voltage signal of 4.5V(VOH) to another inverter, then that signal can fall by 0.5V, all the way to VIH before it becomes an invalid logical 1 input to the second inverter. The width of the forbidden region is defined as VIH−VIL. For this problem, it is 2.5V. Valid inputs to our logic family are not allowed to fall between VIH and VIL. When VGS for the MOSFET is below VT, the MOSFET behaves like an open circuit, and iDS=0. That means no voltage drops over RPUI and the output voltage of our inverter is VS, so this case is fine with out static discipline, since the output voltage is above VOH. For VGS≥VT, the MOSFET is on and behaves like a resistor with resistance RON with our model. To find RPUI: VOL=VS(RON)RON+RPUI 1=5(5000.0)(5000.0+RPUI)→RPUI=20000.0Ω Similar to the inverter case, when either MOSFET is off, no current can flow through the pullup resistor because the MOSFETs and pullup resistor are in series. So VOUT for the NAND gate is simply VS when either MOSFET is off. When both MOSFETs are on, they behave like resistors with resistance RON. The two MOSFETs are in series, so we calculate: To find RPUA: VOL=VS(2RON)2RON+RPUA 1=5(10000.0)(10000.0+RPUA)→RPUA=40000.0Ω When both MOSFETs are off, VOUT for the NOR gate is simply VS because no current can flow through either MOSFET or RPUO. When one MOSFET is on, VOUT is: VS⋅(0.5)RON(0.5)RON+RPUO because the MOSFETs are in parallel with each other. For the cases with one MOSFET on or both MOSFETs on, VOUT must be at least as small as VOL. For the case with one MOSFET on, RPUO must be at least 20000.0 Ω. For the case with both MOSFETs on, RPUO must be at least 10000.0 Ω. So for our NOR gate to satisfy the static discipline, RPUO must be at least 20000.0 Ω. When the MOSFET in the inverter is off, no power is consumed because no current can flow as the MOSFET behaves like an open circuit. When it is on, VS must drop over RPUI and RON, so the power consumed is: (VS)2RPUI+RON Power consumed by inverter: 25V5000.0+20000.0Ω=0.001W When either MOSFET is off, no current flows through the MOSFETs or RPUA, so there is no power consumed. When both MOSFETs are on, VS must drop over RPUA and 2RON because the MOSFETs are in series with each other. The power consumed in this case is: (VS)2RPUA+2RON Power consumed by NAND: 25V2⋅5000.0+40000.0Ω=0.0005W When both MOSFETs are off, no curernt can flow, so no power is consumed. When one MOSFET is on, VS must drop over RPUO and RON, so the power consumed is: (VS)2RPUO+RON When both MOSFETs are on, VS must drop over RPUO and 12 RON because the MOSFETs are in parallel, so the power consumed is: (VS)2RPUO+0.5(RON) The maximum power is consumed by the NOR gate in the latter case: 25V(5000.0∥5000.0)+20000.0Ω=0.001111W
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
i forget the formula..
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
the first one
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
The high noise margin is defined as VOH−VIH
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
The width of the forbidden region is defined as VIH−VIL
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
can u plss solve this for me.. may b some calculation error vT=2, Ron =18000
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
To find RPUI: VOL=VS(RON)/RON+RPUI
 2 years ago

ThundaCheese Group TitleBest ResponseYou've already chosen the best response.0
Rth formula for Q6?
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
yeah.. I'll solve .. one minute .. I don't know yet Thunda.. I am really want to know too
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
I really want *
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
give me the values Vs etc etc ...
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
hey put Isc =0.75 in formula rth=vth/Isc
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
what nurali?
 2 years ago

ThundaCheese Group TitleBest ResponseYou've already chosen the best response.0
Thanks a bunch!!
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
and what about Vol ? what's value yours ?
 2 years ago

Nurali Group TitleBest ResponseYou've already chosen the best response.0
reply aditya
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
short circuit that circuit then calculate the current in that circuit., now that current I=Isc+B*vb
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
try this value 72000 ... because Vol=Vs*Ron/Ron*Rput then we have 1=5*18000/18000+Rput to be 1= 1 the variable Rput is 72000
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
hey for power of nand the formula is : Vs^2/(Rpul+2*Ron) but i got wrong answer
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
I'll help you.. 1 m
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
maybe your Rpua is not correct.. give me this value.. Rpua
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
hey i got.. thanx..:)
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
ooh no problem.. did you get entire Q2 ?
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
can you help with Rth in Q6 ?
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
Isc=0,75.. is it this value that you said ?
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
yupp.. 0.75
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
what is your vth?
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
vout= vth ... it's 3
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
it's my last chance.. it's final check ..
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
is it really 4 ?
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
so wait.. 1st i recheck
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
look my values are Vin=15V, R1=0.5Ω, R2=1.5Ω, R3=5Ω, A=2 and B=1.5.
 2 years ago

aditya16 Group TitleBest ResponseYou've already chosen the best response.3
get correct?
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
yeah... THANK YOU SO MUCH !
 2 years ago

akash97 Group TitleBest ResponseYou've already chosen the best response.0
@kavi11: ur ans 1) 0.45 2)2.7 3)2.7 4)10.8
 2 years ago

xmark Group TitleBest ResponseYou've already chosen the best response.0
@akash97 : how do u get that ? can you post the formula ?
 2 years ago

akash97 Group TitleBest ResponseYou've already chosen the best response.0
@xmark : I got using analysis der is no kind of formula dar I use directly
 2 years ago

Qaisersatti Group TitleBest ResponseYou've already chosen the best response.0
Vin 27 v R1 5 ohm r2 = 7 Ohms R3 12 Ohms A=6 and B=0.1 QNO6 answers please please please ?
 2 years ago

Qaisersatti Group TitleBest ResponseYou've already chosen the best response.0
time is running out for my friend....
 2 years ago

Logan2 Group TitleBest ResponseYou've already chosen the best response.0
question 6 1)Vo* (R3(B*R1*R3)+R1+R2+A*R2)/(R3B*R1*R3)=VIN 2)i1=V0/(R3B*R1*R3) 3)vo = vth 4)Rth=Vth/Isc I=Isc+B*vb
 2 years ago

charansg Group TitleBest ResponseYou've already chosen the best response.0
http://openstudy.com/study#/updates/508b8bc0e4b077c2ef2e9093
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.