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kavi11 Group Title

Rth helpp....Vin =27V , R 1 =5Ω , R 2 =7Ω , R 3 =12Ω , A=6 and B=0.1 .

  • 2 years ago
  • 2 years ago

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  1. aditya16 Group Title
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    put Isc=0.25 in rth=vth/Isc

    • 2 years ago
  2. Logan2 Group Title
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    it's just missing this one to me too .. Does anybody help me too ? Rth ... Vin=15V, R1=0.5Ω, R2=1.5Ω, R3=5Ω, A=2 and B=1.5.

    • 2 years ago
  3. aditya16 Group Title
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    cn u post formula of power in q2

    • 2 years ago
  4. Logan2 Group Title
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    Q2 is the same of HW3.. yeah.. for sure .. one minute !

    • 2 years ago
  5. Logan2 Group Title
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    EXPLANATION: VS=5.0 VOH=4.5 VIH=4.0 VIL=1.5 VOL=1.0 The low noise margin is defined as VIL−VOL. For this problem, it is 0.5V. As an example, if an inverter outputs a valid voltage signal of 1.0V (VOL) to another inverter, then that signal can rise by 0.5V all the way to VIL, before it becomes an invalid logical 0 input to the second inverter. The high noise margin is defined as VOH−VIH. For this problem, it is 0.5V. Again, if an inverter outputs a valid voltage signal of 4.5V(VOH) to another inverter, then that signal can fall by 0.5V, all the way to VIH before it becomes an invalid logical 1 input to the second inverter. The width of the forbidden region is defined as VIH−VIL. For this problem, it is 2.5V. Valid inputs to our logic family are not allowed to fall between VIH and VIL. When VGS for the MOSFET is below VT, the MOSFET behaves like an open circuit, and iDS=0. That means no voltage drops over RPUI and the output voltage of our inverter is VS, so this case is fine with out static discipline, since the output voltage is above VOH. For VGS≥VT, the MOSFET is on and behaves like a resistor with resistance RON with our model. To find RPUI: VOL=VS(RON)RON+RPUI 1=5(5000.0)(5000.0+RPUI)→RPUI=20000.0Ω Similar to the inverter case, when either MOSFET is off, no current can flow through the pullup resistor because the MOSFETs and pullup resistor are in series. So VOUT for the NAND gate is simply VS when either MOSFET is off. When both MOSFETs are on, they behave like resistors with resistance RON. The two MOSFETs are in series, so we calculate: To find RPUA: VOL=VS(2RON)2RON+RPUA 1=5(10000.0)(10000.0+RPUA)→RPUA=40000.0Ω When both MOSFETs are off, VOUT for the NOR gate is simply VS because no current can flow through either MOSFET or RPUO. When one MOSFET is on, VOUT is: VS⋅(0.5)RON(0.5)RON+RPUO because the MOSFETs are in parallel with each other. For the cases with one MOSFET on or both MOSFETs on, VOUT must be at least as small as VOL. For the case with one MOSFET on, RPUO must be at least 20000.0 Ω. For the case with both MOSFETs on, RPUO must be at least 10000.0 Ω. So for our NOR gate to satisfy the static discipline, RPUO must be at least 20000.0 Ω. When the MOSFET in the inverter is off, no power is consumed because no current can flow as the MOSFET behaves like an open circuit. When it is on, VS must drop over RPUI and RON, so the power consumed is: (VS)2RPUI+RON Power consumed by inverter: 25V5000.0+20000.0Ω=0.001W When either MOSFET is off, no current flows through the MOSFETs or RPUA, so there is no power consumed. When both MOSFETs are on, VS must drop over RPUA and 2RON because the MOSFETs are in series with each other. The power consumed in this case is: (VS)2RPUA+2RON Power consumed by NAND: 25V2⋅5000.0+40000.0Ω=0.0005W When both MOSFETs are off, no curernt can flow, so no power is consumed. When one MOSFET is on, VS must drop over RPUO and RON, so the power consumed is: (VS)2RPUO+RON When both MOSFETs are on, VS must drop over RPUO and 12 RON because the MOSFETs are in parallel, so the power consumed is: (VS)2RPUO+0.5(RON) The maximum power is consumed by the NOR gate in the latter case: 25V(5000.0∥5000.0)+20000.0Ω=0.001111W

    • 2 years ago
  6. aditya16 Group Title
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    i forget the formula..

    • 2 years ago
  7. Logan2 Group Title
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    VIL−VOL

    • 2 years ago
  8. Logan2 Group Title
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    the first one

    • 2 years ago
  9. aditya16 Group Title
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    thnx dude

    • 2 years ago
  10. Logan2 Group Title
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    The high noise margin is defined as VOH−VIH

    • 2 years ago
  11. Logan2 Group Title
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    The width of the forbidden region is defined as VIH−VIL

    • 2 years ago
  12. aditya16 Group Title
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    can u plss solve this for me.. may b some calculation error vT=2, Ron =18000

    • 2 years ago
  13. Logan2 Group Title
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    To find RPUI: VOL=VS(RON)/RON+RPUI

    • 2 years ago
  14. ThundaCheese Group Title
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    Rth formula for Q6?

    • 2 years ago
  15. Logan2 Group Title
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    yeah.. I'll solve .. one minute .. I don't know yet Thunda.. I am really want to know too

    • 2 years ago
  16. Logan2 Group Title
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    I really want *

    • 2 years ago
  17. Logan2 Group Title
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    give me the values Vs etc etc ...

    • 2 years ago
  18. aditya16 Group Title
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    hey put Isc =0.75 in formula rth=vth/Isc

    • 2 years ago
  19. aditya16 Group Title
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    Vs=5v

    • 2 years ago
  20. aditya16 Group Title
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    what nurali?

    • 2 years ago
  21. ThundaCheese Group Title
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    Thanks a bunch!!

    • 2 years ago
  22. Logan2 Group Title
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    and what about Vol ? what's value yours ?

    • 2 years ago
  23. Nurali Group Title
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    reply aditya

    • 2 years ago
  24. aditya16 Group Title
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    1 min

    • 2 years ago
  25. aditya16 Group Title
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    short circuit that circuit then calculate the current in that circuit., now that current I=Isc+B*vb

    • 2 years ago
  26. aditya16 Group Title
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    Vol=1V

    • 2 years ago
  27. Logan2 Group Title
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    try this value 72000 ... because Vol=Vs*Ron/Ron*Rput then we have 1=5*18000/18000+Rput to be 1= 1 the variable Rput is 72000

    • 2 years ago
  28. aditya16 Group Title
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    hey for power of nand the formula is : Vs^2/(Rpul+2*Ron) but i got wrong answer

    • 2 years ago
  29. Logan2 Group Title
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    I'll help you.. 1 m

    • 2 years ago
  30. Logan2 Group Title
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    maybe your Rpua is not correct.. give me this value.. Rpua

    • 2 years ago
  31. aditya16 Group Title
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    hey i got.. thanx..:)

    • 2 years ago
  32. Logan2 Group Title
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    ooh no problem.. did you get entire Q2 ?

    • 2 years ago
  33. aditya16 Group Title
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    yup

    • 2 years ago
  34. Logan2 Group Title
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    great !!

    • 2 years ago
  35. Logan2 Group Title
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    can you help with Rth in Q6 ?

    • 2 years ago
  36. Logan2 Group Title
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    Isc=0,75.. is it this value that you said ?

    • 2 years ago
  37. aditya16 Group Title
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    yupp.. 0.75

    • 2 years ago
  38. aditya16 Group Title
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    what is your vth?

    • 2 years ago
  39. Logan2 Group Title
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    it's 3

    • 2 years ago
  40. Logan2 Group Title
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    vout= vth ... it's 3

    • 2 years ago
  41. aditya16 Group Title
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    rth=4

    • 2 years ago
  42. Logan2 Group Title
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    it's my last chance.. it's final check ..

    • 2 years ago
  43. Logan2 Group Title
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    is it really 4 ?

    • 2 years ago
  44. aditya16 Group Title
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    so wait.. 1st i recheck

    • 2 years ago
  45. Logan2 Group Title
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    thank you so much

    • 2 years ago
  46. Logan2 Group Title
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    look my values are Vin=15V, R1=0.5Ω, R2=1.5Ω, R3=5Ω, A=2 and B=1.5.

    • 2 years ago
  47. aditya16 Group Title
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    rth=4

    • 2 years ago
  48. aditya16 Group Title
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    get correct?

    • 2 years ago
  49. Logan2 Group Title
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    yeah... THANK YOU SO MUCH !

    • 2 years ago
  50. akash97 Group Title
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    @kavi11: ur ans 1) 0.45 2)2.7 3)2.7 4)10.8

    • 2 years ago
  51. xmark Group Title
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    @akash97 : how do u get that ? can you post the formula ?

    • 2 years ago
  52. akash97 Group Title
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    @xmark : I got using analysis der is no kind of formula dar I use directly

    • 2 years ago
  53. Qaisersatti Group Title
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    Vin 27 v R1 5 ohm r2 = 7 Ohms R3 12 Ohms A=6 and B=0.1 QNO6 answers please please please ?

    • 2 years ago
  54. Qaisersatti Group Title
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    time is running out for my friend....

    • 2 years ago
  55. Logan2 Group Title
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    question 6 1)Vo* (R3-(B*R1*R3)+R1+R2+A*R2)/(R3-B*R1*R3)=VIN 2)i1=V0/(R3-B*R1*R3) 3)vo = vth 4)Rth=Vth/Isc I=Isc+B*vb

    • 2 years ago
  56. charansg Group Title
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    http://openstudy.com/study#/updates/508b8bc0e4b077c2ef2e9093

    • 2 years ago
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