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apple_pi
Group Title
Factor: x^42x^3+x^2+8x5
Try it manually...how is it done?
 2 years ago
 2 years ago
apple_pi Group Title
Factor: x^42x^3+x^2+8x5 Try it manually...how is it done?
 2 years ago
 2 years ago

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ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Use the rational roots test?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Okay. The possible rational roots are: 5 5 1 1
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Checking all of them. Gimme a sec.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Yup, not 1 and 1.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
no rational roots
 2 years ago

apple_pi Group TitleBest ResponseYou've already chosen the best response.0
yeah, but it can still be factorised
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
into two quadratics... what's the point here?
 2 years ago

apple_pi Group TitleBest ResponseYou've already chosen the best response.0
Well...you're factoring it I guess you could get the roots But how do you get to the quadratics?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Yeah, we can.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
i may suggest a way, (x^2+ax+b)(x^2+cx+d) = x^42x^3+x^2+8x5 and compare the coefficients, 4 unknowns
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Like for example, we have \(\sqrt2{}\) as a root, then a factor would be \(\rm x^2  2\).
 2 years ago

AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
Well, @hartnn 's way is very good to get the quadratics
 2 years ago
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