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apple_pi
Group Title
Factor: x^42x^3+x^2+8x5
Try it manually...how is it done?
 one year ago
 one year ago
apple_pi Group Title
Factor: x^42x^3+x^2+8x5 Try it manually...how is it done?
 one year ago
 one year ago

This Question is Closed

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Use the rational roots test?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Okay. The possible rational roots are: 5 5 1 1
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Checking all of them. Gimme a sec.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
forget 1,1
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Yup, not 1 and 1.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
no rational roots
 one year ago

apple_pi Group TitleBest ResponseYou've already chosen the best response.0
yeah, but it can still be factorised
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
into two quadratics... what's the point here?
 one year ago

apple_pi Group TitleBest ResponseYou've already chosen the best response.0
Well...you're factoring it I guess you could get the roots But how do you get to the quadratics?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Yeah, we can.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
i may suggest a way, (x^2+ax+b)(x^2+cx+d) = x^42x^3+x^2+8x5 and compare the coefficients, 4 unknowns
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Like for example, we have \(\sqrt2{}\) as a root, then a factor would be \(\rm x^2  2\).
 one year ago

AbhimanyuPudi Group TitleBest ResponseYou've already chosen the best response.0
Well, @hartnn 's way is very good to get the quadratics
 one year ago
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