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Factor: x^4-2x^3+x^2+8x-5 Try it is it done?

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Use the rational roots test?
try it
Okay. The possible rational roots are: 5 -5 1 -1

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Other answers:

Checking all of them. Gimme a sec.
forget 1,-1
Yup, not 1 and -1.
not 5.
no rational roots
yeah, but it can still be factorised
into two quadratics... what's the point here?'re factoring it I guess you could get the roots But how do you get to the quadratics?
Yeah, we can.
i may suggest a way, (x^2+ax+b)(x^2+cx+d) = x^4-2x^3+x^2+8x-5 and compare the co-efficients, 4 unknowns
like bd=-5
Like for example, we have \(\sqrt2{}\) as a root, then a factor would be \(\rm x^2 - 2\).
Well, @hartnn 's way is very good to get the quadratics

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