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malibugranprix2000
Group Title
Find the distance d(p1, p2) between the points p1, p2.
p1=(4,4); p2=(5,1)
 one year ago
 one year ago
malibugranprix2000 Group Title
Find the distance d(p1, p2) between the points p1, p2. p1=(4,4); p2=(5,1)
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.1
Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1x_2)^2+(y_1y_2)^2}\) does this help ??
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.1
I got square root of 26 so far.
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.1
if I simplify that it goes into 2 * 13?
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.1
is 2 square root of 13 the answer?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
sqrt 26 is the correct answer u can't simplify that to 2 square root of 13
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.0
I think the formula should be \[\huge d=\sqrt{(x_2x_1)^2+(y_2y_1)^2}\] or is it the same thing?
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.1
how come this answer I got right it was 2 square root of 17 the problem was p1(4,3) pr(2,5)
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.1
it came out to be square root of 68 that couldn't be simplified right?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yeah, \(\huge \sqrt {68}= \sqrt {4*17}= \sqrt 4 \sqrt 17 =2\sqrt17\)
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.1
oh ok I see
 one year ago

malibugranprix2000 Group TitleBest ResponseYou've already chosen the best response.1
thanks
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcomes ^_^
 one year ago
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