Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

malibugranprix2000

  • 3 years ago

Find the distance d(p1, p2) between the points p1, p2. p1=(4,-4); p2=(5,1)

  • This Question is Closed
  1. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\) does this help ??

  2. malibugranprix2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I got square root of 26 so far.

  3. malibugranprix2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if I simplify that it goes into 2 * 13?

  4. malibugranprix2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    is 2 square root of 13 the answer?

  5. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sqrt 26 is the correct answer u can't simplify that to 2 square root of 13

  6. Mimi_x3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I think the formula should be \[\huge d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] or is it the same thing?

  7. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    same thing

  8. malibugranprix2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how come this answer I got right it was 2 square root of 17 the problem was p1(4,-3) pr(2,5)

  9. malibugranprix2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it came out to be square root of 68 that couldn't be simplified right?

  10. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah, \(\huge \sqrt {68}= \sqrt {4*17}= \sqrt 4 \sqrt 17 =2\sqrt17\)

  11. malibugranprix2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh ok I see

  12. malibugranprix2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thanks

  13. hartnn
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    welcomes ^_^

  14. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy