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 2 years ago
hi guys
in lec8 (6.00, 2011), function fact(n)
if i modify it a little(2 different ways) i am getting error whereas i don`t think removing this statement should affect the code..please can you tell me my mistake(also little details about error). Here is the code:
http://pastebin.com/FXpk8NqW
 2 years ago
hi guys in lec8 (6.00, 2011), function fact(n) if i modify it a little(2 different ways) i am getting error whereas i don`t think removing this statement should affect the code..please can you tell me my mistake(also little details about error). Here is the code: http://pastebin.com/FXpk8NqW

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TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1for recursive functions you need to have the option of having a recursive call *and* a base case in each definition. neither of your definitions have base cases like if n==1 or n==0: return 1 ^^^^^^ these are your base cases

harsimran_hs4
 2 years ago
Best ResponseYou've already chosen the best response.0can you explain a little more about base case.... and isn't the assert doing the same....and in the function fact(n) i have removed only if condition i.e if the number being negetive or less than 1 then it should return the same no.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1You need to think a little more mechanically about each step: First of all, assert only limits the types of inputs allowed; it has nothing to do with a base case. The base case is what all possible inputs will tend to as n decreases on each recursive call. Since every recursive call is to n*fact(n  1), this tells us that our input n is decreasing on each call. We will get *no final result* unless this terminates, which without a base case, it does not.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1def fact1(n): assert n >= 0 #makes sure that input is positive and an integer return n*fact1(n1) #calls back to fact1 with an input of one less problem: you have nothing in the code that tells it to terminate. There is no endpoint to this function; it will just call on fact(n1) even after n gets negative. You need a base case to fix this.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1def fact(n): assert n >= 0 if n > 1: return n*fact(n  1) okay, this one is a little better, but you have in no way specified what happens after n==0 all we have are recursive calls to the function again, with no final output. Your only return statement involves another function, so you will get no numerical output.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1it seems to me that you think that the assert operator will give you some return once we get to a point where the input is negative, but it will not. you need another return statement with the base case(s) is the moral of the story.

harsimran_hs4
 2 years ago
Best ResponseYou've already chosen the best response.0i appreciate your efforts to explain but i am little confused how about this code def fact(n): if n > 1: return n*fact(n  1) (if we will run this code i expect to get fact will input 1 less so at some point we will get x=0 and it will terminate but can you explain the error i get while running fact(n) TypeError: unsupported operand type(s) for *: 'int' and 'NoneType'

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1your only return statement is return n*fact(n  1) but when n==2 this is 2*fact(1) but what is fact(1) ? the way you defined the function it's nothing since the function is not defined for n<=1. Therefor Python sees 2*None ^ ^ int None which is a static semantic error

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1try doing type(fact(1)) and you will see it is the None type, because your function is not defined for n<=1

harsimran_hs4
 2 years ago
Best ResponseYou've already chosen the best response.0@TuringTest finally i got the concept thank you
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