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correction \[\frac{ 1 }{ 2 }x=-1 +\sqrt{x+2}\]

What you tried yet @Compgroupmail ?

I tried to bring it to the power by \[\frac{ 1 }{ 4 }x=1+(x+2)\]
/is this correct?

\[\large{\frac{x^2}{4} = 1+x-2 -2\sqrt{x+2}}\]

ok but I still don't understand how you broke it down to that. Can we go through it step by step?

Oh! Sorry I think I confused you, yes why not...
so do you know the identity of (a+b)^2 = ?

a^2+2ab+b^2

Right! so in RHS (Right hand side) we have : -1 + sqrt{x+2} , correct?

left side of equation \[(\frac{ 1 }{ 2 }x)^2= \frac{ 1 }{ 4 }x\].
Correct?

right. That is the right hand side. What's next?

no. Not 100% how to do it. That's what's messing me up.

Wait for 1 minute, I am opening google chrome as IE is quite slow

ok no problem

add 1 to both sides and square both sides
\[(\frac{ x }{ 2 } +1)^2 = x +2\]

\[ \frac{ x^2 }{4 } +x +1 = x+2\]

x^2 =4

ahh. I understand now :) THanks!