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rahul91
 2 years ago
Best ResponseYou've already chosen the best response.1its easy with KVL and laplace transform

nallamala
 2 years ago
Best ResponseYou've already chosen the best response.0first learn the formulas for R L C then automatically u vil get the process

samdol
 2 years ago
Best ResponseYou've already chosen the best response.0V = R*dq/dt + q/c + L*d(dq/dt)/dt (serial connected RLC circuit) dq/dt > k*e^(jwt), (j = (1)^0.5) then V = {R +1/(cjw) + Ljw}*ke^(jwt) then rearrange right side, one is real part, the other is complex part V(real part) = [R^2 + {Lw  1/(cw)}^2]*k*cos(jwttheta) V(complex part) = [R^2 + {Lw  1/(cw)}^2]*k*sin(jwttheta) theta is phasor differece between I to V

skiandblade
 2 years ago
Best ResponseYou've already chosen the best response.0In order ro solve LRC circuits, you should have some background with exponents whicn are covered in Calculus II.
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