Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
AshleyBcdd
Group Title
Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.
 2 years ago
 2 years ago
AshleyBcdd Group Title
Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.
 2 years ago
 2 years ago

This Question is Closed

AshleyBcdd Group TitleBest ResponseYou've already chosen the best response.0
@amistre64 @SheldonEinstein
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.1
I know this, wait!
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.1
@AshleyBcdd prefer to draw a diagram of it first, I mean that of condition
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.1
dw:1351258288836:dw
 2 years ago

mayank06 Group TitleBest ResponseYou've already chosen the best response.1
initial linear momentum=final linear momentum so 0.08*0.5=0.1*0.08+0.05*v v=0.96
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.1
Now, what we have is : the condition I mentioned above in the form of a diagram is of before collision... Now here is the condition of the marbles AFTER collision in the form of a diagram... dw:1351258449229:dw
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.1
now using the law of conservation of momentum : Momentum before collision = Momentum after collision @AshleyBcdd are you getting what I am telling here?
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.1
\[\large{m_A u_A + m_B u_B = m_A v_A + m_B v_B }\] \[\large{0.08 kg\times (0.05 ms^{1}) + 0.05 kg \times 0 ms^{1} = 0.08 kg \times 0.01 ms^{1} \\+ 0.05 kg \times v_B }\]
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.1
you will get : 0.096 after solving for v_B
 2 years ago

AshleyBcdd Group TitleBest ResponseYou've already chosen the best response.0
I'm sorry i was away, yes i understand! thankyou so much :)
 2 years ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.1
You're welcome....
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.