anonymous
  • anonymous
Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@amistre64 @SheldonEinstein
anonymous
  • anonymous
I know this, wait!
anonymous
  • anonymous
@AshleyBcdd prefer to draw a diagram of it first, I mean that of condition

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anonymous
  • anonymous
|dw:1351258288836:dw|
anonymous
  • anonymous
initial linear momentum=final linear momentum so 0.08*0.5=-0.1*0.08+0.05*v v=0.96
anonymous
  • anonymous
Now, what we have is : the condition I mentioned above in the form of a diagram is of before collision... Now here is the condition of the marbles AFTER collision in the form of a diagram... |dw:1351258449229:dw|
anonymous
  • anonymous
now using the law of conservation of momentum : Momentum before collision = Momentum after collision @AshleyBcdd are you getting what I am telling here?
anonymous
  • anonymous
\[\large{m_A u_A + m_B u_B = m_A v_A + m_B v_B }\] \[\large{0.08 kg\times (0.05 ms^{-1}) + 0.05 kg \times 0 ms^{-1} = 0.08 kg \times -0.01 ms^{-1} \\+ 0.05 kg \times v_B }\]
anonymous
  • anonymous
you will get : 0.096 after solving for v_B
anonymous
  • anonymous
I'm sorry i was away, yes i understand! thankyou so much :)
anonymous
  • anonymous
You're welcome....

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