## anonymous 3 years ago Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.

1. anonymous

@amistre64 @SheldonEinstein

2. anonymous

I know this, wait!

3. anonymous

@AshleyBcdd prefer to draw a diagram of it first, I mean that of condition

4. anonymous

|dw:1351258288836:dw|

5. anonymous

initial linear momentum=final linear momentum so 0.08*0.5=-0.1*0.08+0.05*v v=0.96

6. anonymous

Now, what we have is : the condition I mentioned above in the form of a diagram is of before collision... Now here is the condition of the marbles AFTER collision in the form of a diagram... |dw:1351258449229:dw|

7. anonymous

now using the law of conservation of momentum : Momentum before collision = Momentum after collision @AshleyBcdd are you getting what I am telling here?

8. anonymous

$\large{m_A u_A + m_B u_B = m_A v_A + m_B v_B }$ $\large{0.08 kg\times (0.05 ms^{-1}) + 0.05 kg \times 0 ms^{-1} = 0.08 kg \times -0.01 ms^{-1} \\+ 0.05 kg \times v_B }$

9. anonymous

you will get : 0.096 after solving for v_B

10. anonymous

I'm sorry i was away, yes i understand! thankyou so much :)

11. anonymous

You're welcome....