Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

AshleyBcdd

  • 2 years ago

Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.

  • This Question is Closed
  1. AshleyBcdd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @amistre64 @SheldonEinstein

  2. SheldonEinstein
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I know this, wait!

  3. SheldonEinstein
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @AshleyBcdd prefer to draw a diagram of it first, I mean that of condition

  4. SheldonEinstein
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1351258288836:dw|

  5. mayank06
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    initial linear momentum=final linear momentum so 0.08*0.5=-0.1*0.08+0.05*v v=0.96

  6. SheldonEinstein
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Now, what we have is : the condition I mentioned above in the form of a diagram is of before collision... Now here is the condition of the marbles AFTER collision in the form of a diagram... |dw:1351258449229:dw|

  7. SheldonEinstein
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    now using the law of conservation of momentum : Momentum before collision = Momentum after collision @AshleyBcdd are you getting what I am telling here?

  8. SheldonEinstein
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\large{m_A u_A + m_B u_B = m_A v_A + m_B v_B }\] \[\large{0.08 kg\times (0.05 ms^{-1}) + 0.05 kg \times 0 ms^{-1} = 0.08 kg \times -0.01 ms^{-1} \\+ 0.05 kg \times v_B }\]

  9. SheldonEinstein
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you will get : 0.096 after solving for v_B

  10. AshleyBcdd
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm sorry i was away, yes i understand! thankyou so much :)

  11. SheldonEinstein
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You're welcome....

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.