Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

AshleyBcdd Group Title

Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.

  • one year ago
  • one year ago

  • This Question is Closed
  1. AshleyBcdd Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @amistre64 @SheldonEinstein

    • one year ago
  2. SheldonEinstein Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I know this, wait!

    • one year ago
  3. SheldonEinstein Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @AshleyBcdd prefer to draw a diagram of it first, I mean that of condition

    • one year ago
  4. SheldonEinstein Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1351258288836:dw|

    • one year ago
  5. mayank06 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    initial linear momentum=final linear momentum so 0.08*0.5=-0.1*0.08+0.05*v v=0.96

    • one year ago
  6. SheldonEinstein Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Now, what we have is : the condition I mentioned above in the form of a diagram is of before collision... Now here is the condition of the marbles AFTER collision in the form of a diagram... |dw:1351258449229:dw|

    • one year ago
  7. SheldonEinstein Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    now using the law of conservation of momentum : Momentum before collision = Momentum after collision @AshleyBcdd are you getting what I am telling here?

    • one year ago
  8. SheldonEinstein Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\large{m_A u_A + m_B u_B = m_A v_A + m_B v_B }\] \[\large{0.08 kg\times (0.05 ms^{-1}) + 0.05 kg \times 0 ms^{-1} = 0.08 kg \times -0.01 ms^{-1} \\+ 0.05 kg \times v_B }\]

    • one year ago
  9. SheldonEinstein Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    you will get : 0.096 after solving for v_B

    • one year ago
  10. AshleyBcdd Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm sorry i was away, yes i understand! thankyou so much :)

    • one year ago
  11. SheldonEinstein Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You're welcome....

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.