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  • 3 years ago

If the frequency of having light colored hair in the human population is 0.4, and that of having dimples is 0.5, then what is the probability that any given individual will have either light colored hair or dimples or both? (Assume that these traits are independent of one another.) a. 0.7 b. 0.3 c. 0.6 d. 0.2

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  1. blues
    • 3 years ago
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    You will need to use the Hardy Weinburg equation. \[1 = p^2 + 2pq + q^2\] where p^2 is the frequency of the dominant homozygous individuals, 2pq is the frequency of heterozygotes and q^2 is the frequency of recessive homozygous individuals in the total population. Is that helpful enough, or would you like to work through the problem in more detail?

  2. anonymous
    • 3 years ago
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    can yo plz solve the problem using the equation

  3. singularity
    • 8 days ago
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    This has nothing to do with Hardy Weinburg equation. It is a probability math question. Here we are dealing with two non mutually exclusive events. Frequency is the occurrence of of a particular event and can be taken as it's probability to occur. Let us assume P(H) is the probability of light colored hair and P(D) as the probability of Dimples. The union of both events is what is asked here, that is the collection of all event that belong to either or both. P(H ∪ D) = P(H) + P(D) - P(H ∩ D) = 0.4 + 0.5 - (0.4 * 0.5) = 0.7 Here P(H) and P(D) both have a copy of same events where they occur together which is given by P(H ∩ D) = P(H)*P(D) as they are independent of each other and has to subtracted from the sum of probabilities to get the actual number of occurrences.

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