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dennisjr

  • 3 years ago

f(x)=3x^3+4x^2-x+C and f(2)=1 what is the value of c

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  1. Algebraic!
    • 3 years ago
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    put in '2' for 'x' and set the whole thing equal to '1'... then find C

  2. dennisjr
    • 3 years ago
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    ok im trying it

  3. dennisjr
    • 3 years ago
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    so I get fx=3(8)+4(4)-x+c

  4. myininaya
    • 3 years ago
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    Replace all x with 2 So you should have f(2)=3(8)+4(4)-2+c which can be simplified more so

  5. myininaya
    • 3 years ago
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    Then set that =1 and solve for c

  6. fatemeh8989
    • 3 years ago
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    you would get : fx=3(8)+4(4)-2+c = 1 now c is easy to find,right?

  7. dennisjr
    • 3 years ago
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    im trying to work it

  8. fatemeh8989
    • 3 years ago
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    c = 1 - 24 - 16 + 2 which is: -37

  9. tasreeb
    • 3 years ago
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    C=-37

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