anonymous
  • anonymous
f(x)=3x^3+4x^2-x+C and f(2)=1 what is the value of c
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
put in '2' for 'x' and set the whole thing equal to '1'... then find C
anonymous
  • anonymous
ok im trying it
anonymous
  • anonymous
so I get fx=3(8)+4(4)-x+c

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myininaya
  • myininaya
Replace all x with 2 So you should have f(2)=3(8)+4(4)-2+c which can be simplified more so
myininaya
  • myininaya
Then set that =1 and solve for c
anonymous
  • anonymous
you would get : fx=3(8)+4(4)-2+c = 1 now c is easy to find,right?
anonymous
  • anonymous
im trying to work it
anonymous
  • anonymous
c = 1 - 24 - 16 + 2 which is: -37
tasreeb
  • tasreeb
C=-37

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