dennisjr
f(x)=3x^3+4x^2x+C and f(2)=1 what is the value of c



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Algebraic!
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put in '2' for 'x' and set the whole thing equal to '1'... then find C

dennisjr
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ok im trying it

dennisjr
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so I get fx=3(8)+4(4)x+c

myininaya
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Replace all x with 2
So you should have f(2)=3(8)+4(4)2+c which can be simplified more so

myininaya
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Then set that =1 and solve for c

fatemeh8989
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you would get : fx=3(8)+4(4)2+c = 1
now c is easy to find,right?

dennisjr
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im trying to work it

fatemeh8989
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c = 1  24  16 + 2 which is: 37

tasreeb
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C=37