## Biancao9o3o12 3 years ago In set-builder notation, how do you write the solutions of the inequality? 3x + 10 ≥ 4 (1 point) A.{x | x ≥ –2} B. {x | x ≤ 2} C.{x | x ≤ –2} D.{x | x ≥ 2}

1. UnkleRhaukus

$3x + 10 ≥ 4$ minus ten from both sides, then divide both sides by three, what do you get

2. Biancao9o3o12

okay I got -7+10>4

3. UnkleRhaukus

try again

4. Biancao9o3o12

C.{x | x ≤ –2} ?

5. UnkleRhaukus

what do you get after you minus ten from both sides, and divide both sides by three,

6. Biancao9o3o12

I get 3

7. Biancao9o3o12

Loook I don't know how to do this and I have this test that was due 4 days ago and I haven't finished because I thought I could do it but I can't

8. UnkleRhaukus

$3x+10≥4$ minusing ten from both sides, $3x+10-10≥4-10$

9. Biancao9o3o12

Okay 3x+10=13-10>4-10=5

10. UnkleRhaukus

$3x+10−10≥4−10$simplifying $3x≥-6$

11. UnkleRhaukus

now, divide both sides by three,

12. Biancao9o3o12

3>1

13. UnkleRhaukus

$3x≥−6$dividing both sides by three $\frac{3x}3≥\frac{−6}3$ simplify

14. Biancao9o3o12

2>1