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Biancao9o3o12

  • 2 years ago

In set-builder notation, how do you write the solutions of the inequality? 3x + 10 ≥ 4 (1 point) A.{x | x ≥ –2} B. {x | x ≤ 2} C.{x | x ≤ –2} D.{x | x ≥ 2}

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  1. UnkleRhaukus
    • 2 years ago
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    \[3x + 10 ≥ 4 \] minus ten from both sides, then divide both sides by three, what do you get

  2. Biancao9o3o12
    • 2 years ago
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    okay I got -7+10>4

  3. UnkleRhaukus
    • 2 years ago
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    try again

  4. Biancao9o3o12
    • 2 years ago
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    C.{x | x ≤ –2} ?

  5. UnkleRhaukus
    • 2 years ago
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    what do you get after you minus ten from both sides, and divide both sides by three,

  6. Biancao9o3o12
    • 2 years ago
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    I get 3

  7. Biancao9o3o12
    • 2 years ago
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    Loook I don't know how to do this and I have this test that was due 4 days ago and I haven't finished because I thought I could do it but I can't

  8. UnkleRhaukus
    • 2 years ago
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    \[3x+10≥4\] minusing ten from both sides, \[3x+10-10≥4-10\]

  9. Biancao9o3o12
    • 2 years ago
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    Okay 3x+10=13-10>4-10=5

  10. UnkleRhaukus
    • 2 years ago
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    \[3x+10−10≥4−10\]simplifying \[3x≥-6\]

  11. UnkleRhaukus
    • 2 years ago
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    now, divide both sides by three,

  12. Biancao9o3o12
    • 2 years ago
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    3>1

  13. UnkleRhaukus
    • 2 years ago
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    \[3x≥−6\]dividing both sides by three \[\frac{3x}3≥\frac{−6}3\] simplify

  14. Biancao9o3o12
    • 2 years ago
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    2>1

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