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Biancao9o3o12 Group Title

In set-builder notation, how do you write the solutions of the inequality? 3x + 10 ≥ 4 (1 point) A.{x | x ≥ –2} B. {x | x ≤ 2} C.{x | x ≤ –2} D.{x | x ≥ 2}

  • one year ago
  • one year ago

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  1. UnkleRhaukus Group Title
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    \[3x + 10 ≥ 4 \] minus ten from both sides, then divide both sides by three, what do you get

    • one year ago
  2. Biancao9o3o12 Group Title
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    okay I got -7+10>4

    • one year ago
  3. UnkleRhaukus Group Title
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    try again

    • one year ago
  4. Biancao9o3o12 Group Title
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    C.{x | x ≤ –2} ?

    • one year ago
  5. UnkleRhaukus Group Title
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    what do you get after you minus ten from both sides, and divide both sides by three,

    • one year ago
  6. Biancao9o3o12 Group Title
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    I get 3

    • one year ago
  7. Biancao9o3o12 Group Title
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    Loook I don't know how to do this and I have this test that was due 4 days ago and I haven't finished because I thought I could do it but I can't

    • one year ago
  8. UnkleRhaukus Group Title
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    \[3x+10≥4\] minusing ten from both sides, \[3x+10-10≥4-10\]

    • one year ago
  9. Biancao9o3o12 Group Title
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    Okay 3x+10=13-10>4-10=5

    • one year ago
  10. UnkleRhaukus Group Title
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    \[3x+10−10≥4−10\]simplifying \[3x≥-6\]

    • one year ago
  11. UnkleRhaukus Group Title
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    now, divide both sides by three,

    • one year ago
  12. Biancao9o3o12 Group Title
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    3>1

    • one year ago
  13. UnkleRhaukus Group Title
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    \[3x≥−6\]dividing both sides by three \[\frac{3x}3≥\frac{−6}3\] simplify

    • one year ago
  14. Biancao9o3o12 Group Title
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    2>1

    • one year ago
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