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Biancao9o3o12
 3 years ago
In setbuilder notation, how do you write the solutions of the inequality?
–2 – x ≥ – 1 (1 point)
{x  x ≤ 1}
{x  x ≥ 1}
{x  x ≥ –1}
{x  x ≤ –1}
HELP >:(
Biancao9o3o12
 3 years ago
In setbuilder notation, how do you write the solutions of the inequality? –2 – x ≥ – 1 (1 point) {x  x ≤ 1} {x  x ≥ 1} {x  x ≥ –1} {x  x ≤ –1} HELP >:(

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wio
 3 years ago
Best ResponseYou've already chosen the best response.0You need to isolate x. The only tricky part is that if you multiply an inequality by a negative number, it flips.

wio
 3 years ago
Best ResponseYou've already chosen the best response.0No, you didn't flip the inequality sign.

Biancao9o3o12
 3 years ago
Best ResponseYou've already chosen the best response.0i DON'T get it :(

wio
 3 years ago
Best ResponseYou've already chosen the best response.0Suppose you have \(x \geq 4\), what happens when you multiply both sides by \(1\)? You actually get \(x \leq 4\). This doesn't happen with \(=\) because it is sementric... but think about it this way: \[x \geq 4 \rightarrow 0\geq 4+x\rightarrow 4 \geq x \rightarrow x\leq 4\]
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