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In setbuilder notation, how do you write the solutions of the inequality?
–2 – x ≥ – 1 (1 point)
{x  x ≤ 1}
{x  x ≥ 1}
{x  x ≥ –1}
{x  x ≤ –1}
HELP >:(
 one year ago
 one year ago
In setbuilder notation, how do you write the solutions of the inequality? –2 – x ≥ – 1 (1 point) {x  x ≤ 1} {x  x ≥ 1} {x  x ≥ –1} {x  x ≤ –1} HELP >:(
 one year ago
 one year ago

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wioBest ResponseYou've already chosen the best response.0
You need to isolate x. The only tricky part is that if you multiply an inequality by a negative number, it flips.
 one year ago

wioBest ResponseYou've already chosen the best response.0
No, you didn't flip the inequality sign.
 one year ago

Biancao9o3o12Best ResponseYou've already chosen the best response.0
i DON'T get it :(
 one year ago

wioBest ResponseYou've already chosen the best response.0
Suppose you have \(x \geq 4\), what happens when you multiply both sides by \(1\)? You actually get \(x \leq 4\). This doesn't happen with \(=\) because it is sementric... but think about it this way: \[x \geq 4 \rightarrow 0\geq 4+x\rightarrow 4 \geq x \rightarrow x\leq 4\]
 one year ago
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