## Biancao9o3o12 2 years ago In set-builder notation, how do you write the solutions of the inequality? –2 – x ≥ – 1 (1 point) {x | x ≤ 1} {x | x ≥ 1} {x | x ≥ –1} {x | x ≤ –1} HELP >:(

1. wio

You need to isolate x. The only tricky part is that if you multiply an inequality by a negative number, it flips.

2. Biancao9o3o12

{x | x ≥ –1} ?

3. wio

No, you didn't flip the inequality sign.

4. Biancao9o3o12

i DON'T get it :(

5. wio

Suppose you have $$-x \geq 4$$, what happens when you multiply both sides by $$-1$$? You actually get $$x \leq -4$$. This doesn't happen with $$=$$ because it is sementric... but think about it this way: $-x \geq 4 \rightarrow 0\geq 4+x\rightarrow -4 \geq x \rightarrow x\leq -4$