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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
minimise surface area to volume ratio
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[V_{\text{cone}}=\frac {\pi r^2}3\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[SA_\text{cone}=\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[V=\frac{ 1 }{ 3 }\pi r^2 h,h \rightarrow \frac{ 3V }{ \pi r^2}\]\[S=\pi r h_{slant}\] \[S=\pi r \sqrt{r^2+h^2}\] \[S=\pi r \sqrt{r^2+\frac{ 9V }{ \pi^2r^4 }}\] \[S (r)=\sqrt{r^4\pi^2+\frac{ 9V }{ r^2 }}\] \[S'(r)=\frac{(2r^3\pi^29Vr^{3}) }{ \sqrt{r^4\pi^2+\frac{ 9V }{ r^2 }} }\] \[S'(r)=\frac{(2r^3\pi^29Vr^{3}) }{ S }\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
Hence nominator equal to 0 \[2r^3\pi^2=\frac{ 9V }{ r^3 }\] \[r^6=\frac{ 9V }{2\pi^2 } \] i am not sure if this is what you want,,,tried
 one year ago
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