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Counterexample problem.. jus want to know if its right. Thanks!

Mathematics
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x = 1
that looks right:)
thanks! :)

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Other answers:

it's not right
what would happen if you plugged in x=1 ? you get\[x^2\ge1\implies x\ge1\]\[1^2\ge1\implies1\ge1\]where is the falsehood here?
I agree with @TuringTest 1 does equal 1.
ohh yeah.. it wouldnt b false.
but its saying OR equal to
and it is equal, so it's true
@Emah yeahh thats true.. i dont see another answer that works
try each one individually
oh oops i sdidnt see the part that said couterexample:( sorry
ohh its okk
what do you get when you plug in x=2\[x^2\ge1\]\[x\ge1\]are both still true?
i get that its false
which part is false?
first part
\[2^2\ge1\]is not true you say?
Im confused
we need to find an example where the first part is true, and the second part is false to disprove the statement
\[2^2=4\]and four is greater than one, so \[x^2\ge1\]is true for x=2
what about the other part, is\[2\ge1\]?
its true because 2 is greater tha 1
right, so both statements are true for x=2, so this is not a counterexample
what about for x=-3 is\[x^2\ge1\]and is\[x\ge1\]?
first one is 9 > 1 (true) second one is 3 > 1 (true too)
so than its 1/4 (:

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