At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
that looks right:)
it's not right
what would happen if you plugged in x=1 ? you get\[x^2\ge1\implies x\ge1\]\[1^2\ge1\implies1\ge1\]where is the falsehood here?
I agree with @TuringTest 1 does equal 1.
ohh yeah.. it wouldnt b false.
but its saying OR equal to
and it is equal, so it's true
@Emah yeahh thats true.. i dont see another answer that works
try each one individually
oh oops i sdidnt see the part that said couterexample:( sorry
ohh its okk
what do you get when you plug in x=2\[x^2\ge1\]\[x\ge1\]are both still true?
i get that its false
which part is false?
\[2^2\ge1\]is not true you say?
we need to find an example where the first part is true, and the second part is false to disprove the statement
\[2^2=4\]and four is greater than one, so \[x^2\ge1\]is true for x=2
what about the other part, is\[2\ge1\]?
its true because 2 is greater tha 1
right, so both statements are true for x=2, so this is not a counterexample
what about for x=-3 is\[x^2\ge1\]and is\[x\ge1\]?
first one is 9 > 1 (true) second one is 3 > 1 (true too)
so than its 1/4 (: