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kymy_rose00
Group Title
The atomic number of chlorine is 17.
Give the electron configuration for a neutral atom of chlorine. (How do I do this)
 one year ago
 one year ago
kymy_rose00 Group Title
The atomic number of chlorine is 17. Give the electron configuration for a neutral atom of chlorine. (How do I do this)
 one year ago
 one year ago

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saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
Do you know how to use this?
 one year ago

Maddi Group TitleBest ResponseYou've already chosen the best response.1
Atomic number of Strontium = 38 Electronic configuration of Sr = (2, 8, 18, 8, 2) ==> Sr has 2 electrons in outer valence shell, and it would like to lose these 2 electrons and convert itself to a stable octet. ==> Charge of Sr = +2 Atomic number of Chlorine = 17 Electronic configuration of Cl = (2,8,7). ==> Cl has 7 electrons in outer valence shell, and it would like to gain 1 electron and convert itself to a stable octet. ==> Charge of Cl = 1 So, 1 Sr atom needs 2 Cl atoms and vice versa :) ==> SrCl2 is the formula you need... :) I hope i helped you...!
 one year ago

kymy_rose00 Group TitleBest ResponseYou've already chosen the best response.0
I dont understand
 one year ago

Maddi Group TitleBest ResponseYou've already chosen the best response.1
@SheldonEinstein @kymy_rose00 SheldonEinstein can help. Hes great at decsrribing processes.
 one year ago

kymy_rose00 Group TitleBest ResponseYou've already chosen the best response.0
ok thank you
 one year ago

Maddi Group TitleBest ResponseYou've already chosen the best response.1
The electron configuration for neutral Chlorine is 2.8.6.
 one year ago

Carl_Pham Group TitleBest ResponseYou've already chosen the best response.1
Use the Periodic Table. 1. Chlorine is in Period 3, and the noble gas at the end of Period 2, just above, is neon. That gives you a noble gas core of [Ne]. 2. Cl is the 7th element in Period 3, so it will have 7 electrons outside of the noble gas core. 3. Before Cl, you have the 3s block (Na,Mg), so 2 of those 7 electrons will go into the 3s subshell: [Ne] 3s^2. 4. Cl is the 5th of the 6 elements in the 3p block, so the remaining 5 electrons will go into the 3p subshell: [Ne] 3s^2 3p^5. That's it. You can use the n+l rules if you like, but using the Periodic Table is much faster, and you're very likely to always have a PT with you, even on an exam.
 one year ago

Maddi Group TitleBest ResponseYou've already chosen the best response.1
http://www.chem.latech.edu/~deddy/Lectnote/Chap7B.html
 one year ago

Maddi Group TitleBest ResponseYou've already chosen the best response.1
This website surely should help, but @Carl_Pham explained it well. :)
 one year ago

kymy_rose00 Group TitleBest ResponseYou've already chosen the best response.0
So thats the answer?
 one year ago

Maddi Group TitleBest ResponseYou've already chosen the best response.1
The electron configuration for neutral Chlorine is 2.8.6.
 one year ago

Carl_Pham Group TitleBest ResponseYou've already chosen the best response.1
The only thing you may need to keep in mind is how to divide the PT into blocks: dw:1351276806726:dw Keep in mind for this purpose we have to lump He in with H in the 1s block. Also that the p blocks start with 2p, and the d blocks start with 3d.
 one year ago

kymy_rose00 Group TitleBest ResponseYou've already chosen the best response.0
2.8.6?
 one year ago
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