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goongmax

  • 2 years ago

arccos(cos(94pi/59))

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  1. micahwood50
    • 2 years ago
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    HINT: \[\cos^{-1} (\cos x) = x\]

  2. goongmax
    • 2 years ago
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    arccos(cos(94pi/59)) = 94pi/59

  3. zepdrix
    • 2 years ago
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    |dw:1351301061848:dw|

  4. goongmax
    • 2 years ago
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    94pi/59 is in the 4th quad. so... 94pi/59 -pi = 35/59 pi

  5. TransendentialPI
    • 2 years ago
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    We know the range of the arc cosine function is limited to [0,pi], right? We know that 90pi/59 is pretty close to 90pi/60 or 3pi/2. The cos(3pi/2) is close to 0 The arccos(0) is pi/2 The reference angle for the 90pi/59 would be in quad 4 and measure 28/59 pi. SO I'm thiniking the answer to the problem would be 28pi/59|dw:1351301172847:dw|

  6. TransendentialPI
    • 2 years ago
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    Glad to see I was thinking about that correctly.

  7. zepdrix
    • 2 years ago
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    Oh sorry trans.. you were typing really long :C wasn't sure if you were going to paste anything. Didn't mean to step on yer toes there XD

  8. goongmax
    • 2 years ago
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    OMG wrong lol. its 2pi - 94/59pi

  9. goongmax
    • 2 years ago
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    ans: 24/59pi

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