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PoofyPenguin Group Title

Could someone please help me? Attachments to come...

  • one year ago
  • one year ago

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  1. PoofyPenguin Group Title
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    Here is the question:

    • one year ago
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  2. PoofyPenguin Group Title
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    Here's what i got so far:

    • one year ago
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  3. PoofyPenguin Group Title
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    I'm not sure if i did it right and i'm not sure where it's going?

    • one year ago
  4. PoofyPenguin Group Title
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    alright... i think i get it, but i don't get how or why the x becomes and e?

    • one year ago
  5. technopanda13 Group Title
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    fancy writing

    • one year ago
  6. PoofyPenguin Group Title
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    @technopanda13 thank you!

    • one year ago
  7. zepdrix Group Title
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    Haha I was thinking the same thing :D I love that multiply lil astrix XD

    • one year ago
  8. zepdrix Group Title
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    Hmm your steps look really good. I don't see any mistakes. For your final answer I would rewrite the ugly exponential term back as x^(4x^4 + 2), The one in front.

    • one year ago
  9. zepdrix Group Title
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    Oh need an explanation on the exponentiation + log thing?

    • one year ago
  10. baldymcgee6 Group Title
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    Yeah, it looks good to me too. But where did the e and the natural log all the sudden appear from?

    • one year ago
  11. PoofyPenguin Group Title
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    it was part of the hint...but i'm not sure why it works that way...

    • one year ago
  12. baldymcgee6 Group Title
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    What does the question ask?

    • one year ago
  13. PoofyPenguin Group Title
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    @baldymcgee6 have a look at the attachment! it's the one labeld problem 10

    • one year ago
  14. Fazeelayaz Group Title
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    X^(x2+2) is same as e^(4x2+2)lnx u can use calculator to verify

    • one year ago
  15. PoofyPenguin Group Title
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    @Fazeelayaz alright, but how would i go about simplifying it?

    • one year ago
  16. zepdrix Group Title
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    |dw:1351311147700:dw|

    • one year ago
  17. baldymcgee6 Group Title
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    ohh. sorry, I only saw you're answer :/

    • one year ago
  18. PoofyPenguin Group Title
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    @zepdrix i'm glad you like my astrix ;)

    • one year ago
  19. Fazeelayaz Group Title
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    simplyfying the answer or u want to know how they r equal

    • one year ago
  20. PoofyPenguin Group Title
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    @zepdrix great explanation! I understand it now! But how to simplify?

    • one year ago
  21. baldymcgee6 Group Title
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    @PoofyPenguin the reason they give you that hint is to avoid logarithmic differentiation. But for future derivatives, I would recommend learning log diffs. This is just a loophole around it! But good work, it looks good to me.

    • one year ago
  22. zepdrix Group Title
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    |dw:1351311341113:dw|

    • one year ago
  23. zepdrix Group Title
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    Ah yes logarithmic differentiation is a good skill to have c:

    • one year ago
  24. zepdrix Group Title
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    What you have written for f'(x) is perfect poof, you just want to rewrite the first part without the e and natural log, undo your FIRST step that you did to it.

    • one year ago
  25. Fazeelayaz Group Title
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    o i understand there is another way to solve take ln on both sides of ur question the equation becomes \[\ln f(x)=(4x{4}+2)lnx\]

    • one year ago
  26. Fazeelayaz Group Title
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    now differentiate both sides by x

    • one year ago
  27. technopanda13 Group Title
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    __━━____┓━╭━━━━━╮ ____━━____┗┓|::::::::::^━━^ ____━━____━┗|:::::::: |。◕‿‿◕。| ____━━____━━╰O--O----O-O-╯ here is a cat for for all you hard workers

    • one year ago
  28. zepdrix Group Title
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    hah :D

    • one year ago
  29. PoofyPenguin Group Title
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    alright! so would this be the final answer or can it be simplified more?

    • one year ago
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  30. Fazeelayaz Group Title
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    \[1/f(x)*(df(x)/dx)=...\]use product rule on left side

    • one year ago
  31. PoofyPenguin Group Title
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    @technopanda13 cute kitty! ;P

    • one year ago
  32. zepdrix Group Title
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    You could get a common denominator on the inside if you wanted to, but it totally unnecessary c: Yah it looks good there.

    • one year ago
  33. Fazeelayaz Group Title
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    yes u have done it that's right

    • one year ago
  34. PoofyPenguin Group Title
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    ok! let me type it into the computer and get meh marks! :D

    • one year ago
  35. PoofyPenguin Group Title
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    Yayayayayayayay! I got it! Thanks so much everyone! All of you were so helpful! :D

    • one year ago
  36. zepdrix Group Title
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    yay team \:D/

    • one year ago
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