zaphod can anyone explain me, how to do this :) one year ago one year ago

1. zaphod
2. zaphod

@Callisto @ParthKohli @UnkleRhaukus @Hero

3. rajathsbhat

|dw:1351326687906:dw| As you can see, the total horizontal force is $F_x=2F cos \theta \\ where\; cos \theta=\frac{3}{5}$

4. Aperogalics

|dw:1351326544993:dw| In X axis F=2T cos x where x=30/50=3/5[it is twice as OA and AC both components are same] so F=2*4*3/5=24/5=4.8N i.e (C)

5. Aperogalics

But actually if i talk for exactness the information is wrong as elastic force is directly proportional to streching and it changes as we releases so integration is involved and lots more:)

6. zaphod

7. Aperogalics

so u mean none of a , b ,c & d.................:0

8. zaphod

no ur right

9. zaphod

so its like this the resultant of both tension = force

10. Aperogalics

yup

11. Aperogalics

:)

12. rajathsbhat

Why have people stopped giving medals for the help they receive or the responses they like? @Aperogalics deserves a medal for his time and effort :s

13. Aperogalics

ya this time u r correct HIS:) @rajathsbhat

14. zaphod

sorry bro:( i was busy doing my work anyway u both deserve a medal. my apologizes again..

15. rajathsbhat

lol sorry x)

16. Aperogalics

@zaphod i don't work 4 a medal i work 4 only giving knowledge and @rajathsbhat don't be sry it just happens mostly with me:P lolz

17. rajathsbhat

A medal is just a way to say "Your help is appreciated". And don't you agree that it feels good to have someone say that to you?

18. Aperogalics

i really dont know what a medal means here as i join it just 2 days ago:)

19. Aperogalics

@zaphod as the question is completed just close it:)