I have a parabola slide and I am looking for a function of the downhill force which only depends on the x and/or y coordinate.
I came up with a function but I am not sure if this is correct.
You can see everything on the attached picture.
Stacey Warren - Expert brainly.com
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Hmmm... actually I do not know that. It is not specified so it might be better if I write: y=ax^2.
Yes, it just looks kind of ugly if we plug that into the equation for the force.
Is this really the finaly answer?
Can´t we do something to make it simpler or look better? Is there perhaps a different way to determine the force in terms of x and/or y?
|dw:1351340440158:dw|No, its not
Ah... Pythagoras... I see...Now it looks better.
So this is the best we can do?
Simplify sqrt(1+(2ax)^2) maybe
You could try to x/y decompose the force, but that's probably uglier
Although I think it's unsimplifiable
Ok. A big thank you to you, henpen. I really appreciate the help. Thx a lot.
It's probably correct- the force graph looks about right
The Force stands always normal on the slide, right? If so, it does not point at some special point all the time?
|dw:1351349861448:dw| The normal (restrictive) force is always at a normal to the curve