Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

zaphod Group TitleBest ResponseYou've already chosen the best response.1
http://screencast.com/t/v4agnO7Pf
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.1
@ParthKohli @ilikephysics2 @Hero @hartnn
 one year ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.1
f=ma f=m(v/t) 60=30(v/0.50)
 one year ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.1
you r right a=change in vel per time
 one year ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.1
f=m((vu)/t)
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.1
wt answer did u get
 one year ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.1
i did not solve it
 one year ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.1
u=3 met/sec
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.1
yh tell me the answer
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.1
cn u show the working
 one year ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.1
f=60 as it is retarding force f/m=(vu)/t 60/30=(v3)/0.50 2*0.50=v3 1+3=v v=2m/s
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.1
thanks alot :)
 one year ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.1
welcome
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.