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zaphod Group Title

Help needed :)

  • 2 years ago
  • 2 years ago

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  1. zaphod Group Title
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    @03225186213

    • 2 years ago
  2. zaphod Group Title
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    http://screencast.com/t/cquYG2XF

    • 2 years ago
  3. 03225186213 Group Title
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    ihave studid it three years back i have forgotten the formula for ten could u please mention it

    • 2 years ago
  4. zaphod Group Title
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    torque of a couple = one of the force * perpendicular distance between forces

    • 2 years ago
  5. zaphod Group Title
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    can u explain how u got it

    • 2 years ago
  6. 03225186213 Group Title
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    tor on Q=foorce*distance 3=f*0.1(100mm=0.1) f=3/0.1 f=30 this is force on Q as friction neglegible f on P =force on Q tor p=f*distance tor=30N*0.15m (150mm=0.15m) tor=4.5Nm may be i am wrong

    • 2 years ago
  7. zaphod Group Title
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    tension is 60N

    • 2 years ago
  8. 03225186213 Group Title
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    i dont know if u give me formula then i can help you

    • 2 years ago
  9. zaphod Group Title
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    we hve learnt only torque formula, and the moment formula is = force * perpendicular distance for the pivot

    • 2 years ago
  10. supercrazy92 Group Title
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    @03225186213 I think we have to use radius instead of diameter and i got 60N by this..

    • 2 years ago
  11. zaphod Group Title
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    why did u take radius?

    • 2 years ago
  12. supercrazy92 Group Title
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    im not sure let someone correct this...

    • 2 years ago
  13. Kainui Group Title
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    You use radius for sure, because torque is based off the lever arm. It's mounted at the center and you apply torque at the outer ends of the pulley.

    • 2 years ago
  14. Kainui Group Title
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    Think of it like a door. The hinges are at the center of a circle that the door sweeps out when you push it.

    • 2 years ago
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