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zaphod
 2 years ago
Help needed :)
zaphod
 2 years ago
Help needed :)

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03225186213
 2 years ago
Best ResponseYou've already chosen the best response.0ihave studid it three years back i have forgotten the formula for ten could u please mention it

zaphod
 2 years ago
Best ResponseYou've already chosen the best response.0torque of a couple = one of the force * perpendicular distance between forces

zaphod
 2 years ago
Best ResponseYou've already chosen the best response.0can u explain how u got it

03225186213
 2 years ago
Best ResponseYou've already chosen the best response.0tor on Q=foorce*distance 3=f*0.1(100mm=0.1) f=3/0.1 f=30 this is force on Q as friction neglegible f on P =force on Q tor p=f*distance tor=30N*0.15m (150mm=0.15m) tor=4.5Nm may be i am wrong

03225186213
 2 years ago
Best ResponseYou've already chosen the best response.0i dont know if u give me formula then i can help you

zaphod
 2 years ago
Best ResponseYou've already chosen the best response.0we hve learnt only torque formula, and the moment formula is = force * perpendicular distance for the pivot

supercrazy92
 2 years ago
Best ResponseYou've already chosen the best response.0@03225186213 I think we have to use radius instead of diameter and i got 60N by this..

supercrazy92
 2 years ago
Best ResponseYou've already chosen the best response.0im not sure let someone correct this...

Kainui
 2 years ago
Best ResponseYou've already chosen the best response.2You use radius for sure, because torque is based off the lever arm. It's mounted at the center and you apply torque at the outer ends of the pulley.

Kainui
 2 years ago
Best ResponseYou've already chosen the best response.2Think of it like a door. The hinges are at the center of a circle that the door sweeps out when you push it.
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