anonymous
  • anonymous
A spring with a force constant 400 N/m hangs vertically. You attach a 2.2 kg block to it and allow the mass to fall. What is the max distance the block will fall before it begins moving upward?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
The concept: the change in potential energy of the block is EXACTLY equal to the elastic potential energy of the spring. Does that help?
anonymous
  • anonymous
ya a little
anonymous
  • anonymous
i'll get 21.5x = 405x^2 know what?

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anonymous
  • anonymous
elastic potential energy is give by 1/2 kx^2. So how can you get 405x^2 ?
anonymous
  • anonymous
*given
anonymous
  • anonymous
* 200 x^2
anonymous
  • anonymous
there you go. So now, all you have to do is... simplify.
anonymous
  • anonymous
that's the part i have trouble with
anonymous
  • anonymous
Just cancel 1 'x' on both sides.
anonymous
  • anonymous
oh ya
anonymous
  • anonymous
so it would be 11 cm?
anonymous
  • anonymous
yep. 10.75 cm.
anonymous
  • anonymous
ok thanks a lot
anonymous
  • anonymous
:)

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