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sparkly16

  • 3 years ago

A spring with a force constant 400 N/m hangs vertically. You attach a 2.2 kg block to it and allow the mass to fall. What is the max distance the block will fall before it begins moving upward?

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  1. rajathsbhat
    • 3 years ago
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    The concept: the change in potential energy of the block is EXACTLY equal to the elastic potential energy of the spring. Does that help?

  2. sparkly16
    • 3 years ago
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    ya a little

  3. sparkly16
    • 3 years ago
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    i'll get 21.5x = 405x^2 know what?

  4. rajathsbhat
    • 3 years ago
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    elastic potential energy is give by 1/2 kx^2. So how can you get 405x^2 ?

  5. rajathsbhat
    • 3 years ago
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    *given

  6. sparkly16
    • 3 years ago
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    * 200 x^2

  7. rajathsbhat
    • 3 years ago
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    there you go. So now, all you have to do is... simplify.

  8. sparkly16
    • 3 years ago
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    that's the part i have trouble with

  9. rajathsbhat
    • 3 years ago
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    Just cancel 1 'x' on both sides.

  10. sparkly16
    • 3 years ago
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    oh ya

  11. sparkly16
    • 3 years ago
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    so it would be 11 cm?

  12. rajathsbhat
    • 3 years ago
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    yep. 10.75 cm.

  13. sparkly16
    • 3 years ago
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    ok thanks a lot

  14. rajathsbhat
    • 3 years ago
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    :)

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