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A spring with a force constant 400 N/m hangs vertically. You attach a 2.2 kg block to it and allow the mass to fall. What is the max distance the block will fall before it begins moving upward?
 one year ago
 one year ago
A spring with a force constant 400 N/m hangs vertically. You attach a 2.2 kg block to it and allow the mass to fall. What is the max distance the block will fall before it begins moving upward?
 one year ago
 one year ago

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rajathsbhatBest ResponseYou've already chosen the best response.2
The concept: the change in potential energy of the block is EXACTLY equal to the elastic potential energy of the spring. Does that help?
 one year ago

sparkly16Best ResponseYou've already chosen the best response.1
i'll get 21.5x = 405x^2 know what?
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.2
elastic potential energy is give by 1/2 kx^2. So how can you get 405x^2 ?
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.2
there you go. So now, all you have to do is... simplify.
 one year ago

sparkly16Best ResponseYou've already chosen the best response.1
that's the part i have trouble with
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.2
Just cancel 1 'x' on both sides.
 one year ago

sparkly16Best ResponseYou've already chosen the best response.1
so it would be 11 cm?
 one year ago
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