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A spring with a force constant 400 N/m hangs vertically. You attach a 2.2 kg block to it and allow the mass to fall. What is the max distance the block will fall before it begins moving upward?

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The concept: the change in potential energy of the block is EXACTLY equal to the elastic potential energy of the spring. Does that help?
ya a little
i'll get 21.5x = 405x^2 know what?

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Other answers:

elastic potential energy is give by 1/2 kx^2. So how can you get 405x^2 ?
* 200 x^2
there you go. So now, all you have to do is... simplify.
that's the part i have trouble with
Just cancel 1 'x' on both sides.
oh ya
so it would be 11 cm?
yep. 10.75 cm.
ok thanks a lot

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