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 2 years ago
Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?
 2 years ago
Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?

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gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.1g = G M/((R+h)^2) where h is 3.59 10^7 m

gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.1G is gravity constanta, and M is mass of earth..,

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1but the formula dw:1351351359708:dw

gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1351351437651:dw

gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.1the magnitude of the acceleration due to gravity is g..., W is force due to gravity

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.1for m and r what should the values be

gerryliyana
 2 years ago
Best ResponseYou've already chosen the best response.1M is mass of the earth,,, and r is radius of the earth
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