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Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?
 one year ago
 one year ago
Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?
 one year ago
 one year ago

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gerryliyanaBest ResponseYou've already chosen the best response.1
g = G M/((R+h)^2) where h is 3.59 10^7 m
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.1
G is gravity constanta, and M is mass of earth..,
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.1
but the formula dw:1351351359708:dw
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.1
dw:1351351437651:dw
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.1
the magnitude of the acceleration due to gravity is g..., W is force due to gravity
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.1
for m and r what should the values be
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.1
M is mass of the earth,,, and r is radius of the earth
 one year ago
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