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Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?

Physics
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g = G M/((R+h)^2) where h is 3.59 10^7 m
G is gravity constanta, and M is mass of earth..,
but the formula |dw:1351351359708:dw|

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Other answers:

No....
i mean W not g
|dw:1351351437651:dw|
the magnitude of the acceleration due to gravity is g..., W is force due to gravity
for m and r what should the values be
M is mass of the earth,,, and r is radius of the earth
al right thx
ur welcome ^^

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