ksaimouli
  • ksaimouli
Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?
Physics
chestercat
  • chestercat
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anonymous
  • anonymous
g = G M/((R+h)^2) where h is 3.59 10^7 m
anonymous
  • anonymous
G is gravity constanta, and M is mass of earth..,
ksaimouli
  • ksaimouli
but the formula |dw:1351351359708:dw|

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anonymous
  • anonymous
No....
ksaimouli
  • ksaimouli
i mean W not g
anonymous
  • anonymous
|dw:1351351437651:dw|
anonymous
  • anonymous
the magnitude of the acceleration due to gravity is g..., W is force due to gravity
ksaimouli
  • ksaimouli
for m and r what should the values be
anonymous
  • anonymous
M is mass of the earth,,, and r is radius of the earth
ksaimouli
  • ksaimouli
al right thx
anonymous
  • anonymous
ur welcome ^^

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