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ksaimouli Group Title

Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?

  • one year ago
  • one year ago

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  1. gerryliyana Group Title
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    g = G M/((R+h)^2) where h is 3.59 10^7 m

    • one year ago
  2. gerryliyana Group Title
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    G is gravity constanta, and M is mass of earth..,

    • one year ago
  3. ksaimouli Group Title
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    but the formula |dw:1351351359708:dw|

    • one year ago
  4. gerryliyana Group Title
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    No....

    • one year ago
  5. ksaimouli Group Title
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    i mean W not g

    • one year ago
  6. gerryliyana Group Title
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    |dw:1351351437651:dw|

    • one year ago
  7. gerryliyana Group Title
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    the magnitude of the acceleration due to gravity is g..., W is force due to gravity

    • one year ago
  8. ksaimouli Group Title
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    for m and r what should the values be

    • one year ago
  9. gerryliyana Group Title
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    M is mass of the earth,,, and r is radius of the earth

    • one year ago
  10. ksaimouli Group Title
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    al right thx

    • one year ago
  11. gerryliyana Group Title
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    ur welcome ^^

    • one year ago
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