ksaimouli
Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?
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gerryliyana
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g = G M/((R+h)^2)
where h is 3.59 10^7 m
gerryliyana
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G is gravity constanta, and M is mass of earth..,
ksaimouli
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but the formula |dw:1351351359708:dw|
gerryliyana
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No....
ksaimouli
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i mean W not g
gerryliyana
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|dw:1351351437651:dw|
gerryliyana
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the magnitude of the acceleration due to gravity is g..., W is force due to gravity
ksaimouli
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for m and r what should the values be
gerryliyana
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M is mass of the earth,,, and r is radius of the earth
ksaimouli
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al right thx
gerryliyana
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ur welcome ^^