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ksaimouli

  • 3 years ago

Synchronous communications satellites are placed in a circular orbit that is 3.59 10^7 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?

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  1. gerryliyana
    • 3 years ago
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    g = G M/((R+h)^2) where h is 3.59 10^7 m

  2. gerryliyana
    • 3 years ago
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    G is gravity constanta, and M is mass of earth..,

  3. ksaimouli
    • 3 years ago
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    but the formula |dw:1351351359708:dw|

  4. gerryliyana
    • 3 years ago
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    No....

  5. ksaimouli
    • 3 years ago
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    i mean W not g

  6. gerryliyana
    • 3 years ago
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    |dw:1351351437651:dw|

  7. gerryliyana
    • 3 years ago
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    the magnitude of the acceleration due to gravity is g..., W is force due to gravity

  8. ksaimouli
    • 3 years ago
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    for m and r what should the values be

  9. gerryliyana
    • 3 years ago
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    M is mass of the earth,,, and r is radius of the earth

  10. ksaimouli
    • 3 years ago
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    al right thx

  11. gerryliyana
    • 3 years ago
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    ur welcome ^^

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