Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
henpen
Group Title
Power and work
\[ W= \int P dt = \int Fv dt= m \int \frac{dv}{dt} vdt=m \int vdv= \frac{1}{2}m(v_1^2v_0^2) \]
Is this true?:
Did I oversimplify somewhere?
Is this unphysical?
 2 years ago
 2 years ago
henpen Group Title
Power and work \[ W= \int P dt = \int Fv dt= m \int \frac{dv}{dt} vdt=m \int vdv= \frac{1}{2}m(v_1^2v_0^2) \] Is this true?: Did I oversimplify somewhere? Is this unphysical?
 2 years ago
 2 years ago

This Question is Closed

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[ W= \int\limits P dt = \int\limits Fv dt= m \int\limits \frac{dv}{dt} vdt=m \int\limits vdv= \frac{1}{2}m(v_1^2v_0^2) \]
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
it's fine.
 2 years ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.0
correct
 2 years ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
Similarly, \[W=\int\limits_{}^{}Fdx=\int\limits_{}^{}madx=m \int\limits_{}^{} \frac{ dv }{ dt } dx=m \int\limits_{}^{} \frac{ dv }{ dx }\frac{ dx }{ dt } dx = m \int\limits_{}^{} v dv=\frac{ 1 }{ 2 }mv^2\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
@Kainui That's what I did.
 2 years ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
No, you did something slightly different. You used power, I did not.
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.