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anonymous
 3 years ago
Power and work
\[ W= \int P dt = \int Fv dt= m \int \frac{dv}{dt} vdt=m \int vdv= \frac{1}{2}m(v_1^2v_0^2) \]
Is this true?:
Did I oversimplify somewhere?
Is this unphysical?
anonymous
 3 years ago
Power and work \[ W= \int P dt = \int Fv dt= m \int \frac{dv}{dt} vdt=m \int vdv= \frac{1}{2}m(v_1^2v_0^2) \] Is this true?: Did I oversimplify somewhere? Is this unphysical?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ W= \int\limits P dt = \int\limits Fv dt= m \int\limits \frac{dv}{dt} vdt=m \int\limits vdv= \frac{1}{2}m(v_1^2v_0^2) \]

Kainui
 3 years ago
Best ResponseYou've already chosen the best response.0Similarly, \[W=\int\limits_{}^{}Fdx=\int\limits_{}^{}madx=m \int\limits_{}^{} \frac{ dv }{ dt } dx=m \int\limits_{}^{} \frac{ dv }{ dx }\frac{ dx }{ dt } dx = m \int\limits_{}^{} v dv=\frac{ 1 }{ 2 }mv^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Kainui That's what I did.

Kainui
 3 years ago
Best ResponseYou've already chosen the best response.0No, you did something slightly different. You used power, I did not.
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