A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Power and work
\[ W= \int P dt = \int Fv dt= m \int \frac{dv}{dt} vdt=m \int vdv= \frac{1}{2}m(v_1^2v_0^2) \]
Is this true?:
Did I oversimplify somewhere?
Is this unphysical?
anonymous
 4 years ago
Power and work \[ W= \int P dt = \int Fv dt= m \int \frac{dv}{dt} vdt=m \int vdv= \frac{1}{2}m(v_1^2v_0^2) \] Is this true?: Did I oversimplify somewhere? Is this unphysical?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[ W= \int\limits P dt = \int\limits Fv dt= m \int\limits \frac{dv}{dt} vdt=m \int\limits vdv= \frac{1}{2}m(v_1^2v_0^2) \]

Kainui
 4 years ago
Best ResponseYou've already chosen the best response.0Similarly, \[W=\int\limits_{}^{}Fdx=\int\limits_{}^{}madx=m \int\limits_{}^{} \frac{ dv }{ dt } dx=m \int\limits_{}^{} \frac{ dv }{ dx }\frac{ dx }{ dt } dx = m \int\limits_{}^{} v dv=\frac{ 1 }{ 2 }mv^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Kainui That's what I did.

Kainui
 4 years ago
Best ResponseYou've already chosen the best response.0No, you did something slightly different. You used power, I did not.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.