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Multiply (a+4)^3 I have a^3+12a^2+?a+64 I am having trouble finding the number with the ?a

Mathematics
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ok the answer that i have that is really not completed is correct or not?
ok i will try i am kinda rusty on this i havent did this for a long time
For (a+4)^3 (a+4)^3=(a+4)(a+4)(a+4) So, you can apply FOIL to (a+4)(a+4)(a+4) , two times. It is not complete, you have to apply the FOIL method, (a+4)(a+4)(a+4) When you distribute, you will get (a^2+8a+16)(a+4) Then try expanding it again.

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Other answers:

There are some examples learning FOIL here: http://www.mathsisfun.com/algebra/polynomials-multiplying.html
a*a*a=a^3 4+4+4=12a
no.. it is 48a
48a where i have my ? at
i am trying to figure out how o get that number thats all and i keep getting answers that is not helping on how to find...
so could you please show me how did you get 48a?
\[(a+b)^3=a^3+3a^2b+3ab^2+b^3\]
Or If u knw Binomial Theorem Use it..)
ok lets see here i am going to figure out how you got 48a
(a^2+8a+16)(a+4) When you're here, there's a shortcut to look at the coefficient of a, you look at which multiples gives you 'a'. From here you can see that 8a multiply by 4 gives you 32a And 16 multiply by a gives you 16a Since its adding up, 32a+16a=48a
thank you so it is a^3+12a^2+48a+64
ok i dont remember using that it has been years so some of this stough i remember how to....
i feel old brained
ohhhh k
now i get it i am so sorry ppl thank you so much for bearing with me i havent been in school fo a long time and i am warming up on old math memories

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