##Can someone explains the different outcome if I ##change 0.1 to 0.5 at line " ans = ans + 0.1"
## while x = 8 ?
x = float(raw_input('Enter a number:'))
ans = 0.0
print type (ans)
while ans*ans*ans < abs(x):
ans = ans+0.1
## ans = ans +0.5
if ans*ans*ans != abs(x):
print x , ' is not a perfect cube'
ans = -ans
print 'Cube root of ', str(x), 'is' , str(ans)
MIT 6.00 Intro Computer Science (OCW)
Stacey Warren - Expert brainly.com
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I'm slightly confused. A perfect cube should had a cube root that is an integer, so why are you using a float here?
If you change the line to ans = ans + 0.5, then you're going to be checking less cube roots. For example you wont check 0.1 or 0.2 or 0.3 or 0.4. Thus you have a greater probability of missing the cube root.
There are better ways of finding the cube root, by the way. Like using Newton's root finding method.
Also, because you are checking fewer times (at a greater interval), that will impact the accuracy of your program's result.
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please use the pasting websites to paste your code
definitely for the computation of a perfect cube you just need to increase the ans by 1
also you might be confused that you should not get 'not a perfect cube' , it is because of float point error.(the way computer perceives the number may be a little different than you may think)