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Letg(x) = sqrt of x sin(1/x) a) Does lim x goes to 0+ g(x), lim x goes to 0- g(x), mil x goes to 0 g(x) exist? if so what is it? if not why not?

Calculus1
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|dw:1351356869555:dw|
|dw:1351357299352:dw|
x->0+|dw:1351357393544:dw|

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Other answers:

But for x->0- it has no a real limit
so whne x goes to 0+ and lim x goes to 0 is 0?
can you explain how you get these answers by using the given graph?
Yes, your figure is shows the limit is zero.
|dw:1351357624979:dw|
oh okay, but why does the lim x goes to 0 negative does not hve a lim?
oh okay, but why does the lim x goes to 0 negative does not hve a lim?
oh okay, but why does the lim x goes to 0 negative does not hve a lim?
because |dw:1351358916070:dw|

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