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chrislb22

Compute the derivative dy/dx [(x^3 + 8x)(x^2 − x)] | x= 2

  • one year ago
  • one year ago

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  1. angela210793
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    can u go on urself?|dw:1351364346994:dw|

    • one year ago
  2. chrislb22
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    the last part of the equation is cut off

    • one year ago
  3. baldymcgee6
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    |dw:1351368595224:dw|

    • one year ago
  4. baldymcgee6
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    So all you have left to do is to compute the derivatives of (x^3+8x) and (x^2-x).... Lets start with x^3+8x: |dw:1351368680013:dw|

    • one year ago
  5. chrislb22
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    so 3x^2+ 8

    • one year ago
  6. baldymcgee6
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    |dw:1351368877079:dw|

    • one year ago
  7. chrislb22
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    2x-1

    • one year ago
  8. baldymcgee6
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    |dw:1351369084559:dw|

    • one year ago
  9. baldymcgee6
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    You should be able to put it all together now

    • one year ago
  10. chrislb22
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    so (x^3+8x)(2x-1) + (3x^2+8)(x^3+8x)

    • one year ago
  11. baldymcgee6
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    not quite...

    • one year ago
  12. baldymcgee6
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    |dw:1351369459007:dw|

    • one year ago
  13. chrislb22
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    the last part of the equation is cut off (2x- ...

    • one year ago
  14. baldymcgee6
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    2x-1

    • one year ago
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