I'm not sure if this is even solvable, but I'd like to know what sort of things you would need to solve this: \[y''+k(y')^2y=0 \]

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I'm not sure if this is even solvable, but I'd like to know what sort of things you would need to solve this: \[y''+k(y')^2y=0 \]

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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What are you looking for?
I'm guessing y, but you didn't specify.
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|dw:1351369416936:dw|
Nice. I was only able to see y=c as the trivial solution.
there are two answers that one of them is y=c1
I knew there was another one, but I was stuck after y=c. :">
Thank you for that, sorry for being ambiguous in the question.

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