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anonymous
 4 years ago
I'm not sure if this is even solvable, but I'd like to know what sort of things you would need to solve this: \[y''+k(y')^2y=0 \]
anonymous
 4 years ago
I'm not sure if this is even solvable, but I'd like to know what sort of things you would need to solve this: \[y''+k(y')^2y=0 \]

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baldymcgee6
 4 years ago
Best ResponseYou've already chosen the best response.0What are you looking for?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm guessing y, but you didn't specify.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351369287726:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351369416936:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nice. I was only able to see y=c as the trivial solution.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there are two answers that one of them is y=c1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I knew there was another one, but I was stuck after y=c. :">

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you for that, sorry for being ambiguous in the question.
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