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henpen

  • 3 years ago

I'm not sure if this is even solvable, but I'd like to know what sort of things you would need to solve this: \[y''+k(y')^2y=0 \]

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  1. baldymcgee6
    • 3 years ago
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    What are you looking for?

  2. CliffSedge
    • 3 years ago
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    I'm guessing y, but you didn't specify.

  3. mahmit2012
    • 3 years ago
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    |dw:1351369287726:dw|

  4. mahmit2012
    • 3 years ago
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    |dw:1351369416936:dw|

  5. CliffSedge
    • 3 years ago
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    Nice. I was only able to see y=c as the trivial solution.

  6. mahmit2012
    • 3 years ago
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    there are two answers that one of them is y=c1

  7. CliffSedge
    • 3 years ago
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    I knew there was another one, but I was stuck after y=c. :">

  8. henpen
    • 3 years ago
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    Thank you for that, sorry for being ambiguous in the question.

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