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sapphers

  • 2 years ago

|4x + 3y ≥ 30 |x + 3y ≥ 21 |x ≥ 0, y ≥ 0 -- Minimun for C = 5x + 8y 1. List all vertices of the feasible region as ordered pairs. 2. List the values of the objective function for each vertex. 3. List the maximum or minimum amount, including the x, and y-value, of the objective function. I really really need help! I don't understand what to do.

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  1. jarobins
    • 2 years ago
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    Are you having issues graphing these equations?

  2. sapphers
    • 2 years ago
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    Yes. Just all of it. I did the first step which was to rewrite the constraints in slope-intercept form. I just don't really know what to do from there.

  3. jarobins
    • 2 years ago
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    ok so I would graph out your constraints to see how many vertices you have.

  4. sapphers
    • 2 years ago
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    How do you do that?

  5. jarobins
    • 2 years ago
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    |dw:1351370399352:dw|

  6. jarobins
    • 2 years ago
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    so if this is a graph of x and y these are the constrants that x >= 0 and y>=0

  7. sapphers
    • 2 years ago
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    Okay yeah, that makes sense because you can't go less than 0 (negative numbers).. right?

  8. jarobins
    • 2 years ago
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    right

  9. sapphers
    • 2 years ago
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    I found the maximum. I got 62.76. Is that right?

  10. jarobins
    • 2 years ago
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    your other two constraints when converted into slope intercept will be y>= -(x/3) + 7 y>= -(4x/3) + 10 which you said you did, give me a sec and I will graph them

  11. sapphers
    • 2 years ago
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    Yeah, that's what I got.

  12. jarobins
    • 2 years ago
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    |dw:1351370707098:dw|

  13. jarobins
    • 2 years ago
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    so here is your region to work with

  14. sapphers
    • 2 years ago
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    Okay! Now I need to find the ordered pairs?

  15. jarobins
    • 2 years ago
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    right, to do that you need to just go through the region and find the pairs. That quite involved though...

  16. sapphers
    • 2 years ago
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    I'm kind of confused on how to do that.

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