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zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Hmm do you remember what the graph for cosine looks like?

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0I'm pretty sure cos(x) = x only has one solution

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1351373928927:dw This is kind of the idea rose :D At this particular point, the x value and the cosx value are the same.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1So in your picture, x=pi/2 but cosx = 0 Hmm that point doesn't work so well :c

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0okay, i will consider the picture that you showed

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Yah I can't think of the proper way to explain it :D It probably has something to do with the fact that cosine oscillates back and forth between 1 and 1, and since it is continuous it would have to have a solution :d i dunno... just think about it i guess :3 heh

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0Since the function y = x has a domain of all real numbers... as is cos(x), there must be a point of intersection somewhere

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0So which one should I consider now? i have two answers here

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0Combine them... you could say.. Since both y=x and the cosine function have a domain of all real numbers and both are continuous at least one point of intersection is definite.

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0oh okay, thank you so much guys

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2use the intermediate value theorem

latremese40
 2 years ago
Best ResponseYou've already chosen the best response.0roelin i think you did it right
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