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anonymous
 3 years ago
Pleasee help x.x 1. Solve the system by elimination 2x+2y+3z=0
2xy+z=3
2x+3y+3z=5
2.Solve using substitution
xyz=8
4x+4y+5z=7
2x+2z=4
Thanks for any help :o
anonymous
 3 years ago
Pleasee help x.x 1. Solve the system by elimination 2x+2y+3z=0 2xy+z=3 2x+3y+3z=5 2.Solve using substitution xyz=8 4x+4y+5z=7 2x+2z=4 Thanks for any help :o

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0__━━____┓━╭━━━━━╮ ____━━____┗┓::::::::::^━━^ ____━━____━┗:::::::: ｡◕‿‿◕｡ ____━━____━━╰OOOO╯

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm really really bad at solving 3 variable systems but it's imparitive that I at least get these 2 right x.x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Erm not usually haha, simple ones sure but I'm not good with math at all :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you are mean nincompoop

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha technopanda your silly.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im not silly your just jelouis of my mad skillz ┏(_)┛┗(_ )┓┗(_)┛┏(_)┓

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I wish I could see your mad problem solving skills Panda.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0╔══╗♫ ║██║ ║(o) ║ ╚══╝
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