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JayDS Group TitleBest ResponseYou've already chosen the best response.1
\[y=3^{x}\] \[y=_{5}x\]
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
the inverse is just if you put in an x and get a y the inverse is like putting in the y and getting the same x you put in the first part.
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
yep, I did that.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
what you can do is switch your x's and y's then just solve for y.
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
\[y=3^{x}\] \[x=3^{y}\] \[\log _{10}x = \log _{10}3^{y}\] \[\log _{10} x = ylog _{10}3\] \[y=\frac{\log _{10}x}{\log _{10}3}\] y=x/3?
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
I have answers but I want to know what I did wrong, because it seems right to me.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
i think you need to keep the logs or put e^y
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
you can only take away the logs like you did if y had one on that side
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
i think it can be rewrote as y=ln(x3) but i'm a little rusty with logarithms
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
but there is log10 on both sides, so I can cancel it out? and ok... I'm still confused sorry.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
when you moved the y over to the other sice you had y=log(x)/log(3) y doesn't have a log
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
if it was log(y)=log(x)/log(3) you could cancel them out
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
really? hmmm, confusing but I know what you mean.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
yeah i get confused too when you start using logs
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
if you have the answer try to work it backwards to get the first question and try to tie the two to gether with what your sure of.
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
the answer is \[\log _{3}x for x>0\] can you help me out? I don't understand how they got it.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
log 2 x or log 3 x?
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
\[\log_{a}y=x \] is \[a^{x}=y\]
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
from log10(x)=ylog10(3) can you show me the rest of the steps?
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
so we can rewriteyour first one as as\[\log_{3} x=y\]
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
after you switch the x and y I believe?
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
sorry i'm trying to remember this as we go
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
no that is just rewriting it then we swith and solve for x
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
you wrote it wrong then.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
all i did was change the exponent to a log
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
\[y=3^{x}\] \[\log _{3}y=x\]
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
I think you got confused with the x and y, you just got them in the wrong position.
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
then we can switch the x & y from there.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
it's hard to do math on these boards lol
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
yeh I know haha, especially trying to write the equation takes years.
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
using the equation tab*
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
i think i have it let me check with my calculator
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
ok lol i can't figure out how to do it on my calculator but i think it's right, so all we are doing is changing the question into a log of the same equasion then when we swap x and y we already have the answer
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
by the rules of logarithms we have loga^b=c is the same as a^c=b
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
ok, and it turns out to be\[y=\log _{3}x\] right?
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
so taking your problem y=3^x and putting it in log form we get log3^y=x then we swap y and x to get log3^x=y is that right?
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
so let's try the second one
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
y=5^x is log5^y=x so swap is log5^x=y
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
yep but the answer only says 5^x for some reason.
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
confusing, I'll just have to ask my teacher. I'm just doing it advanced anyway.
 2 years ago

JayDS Group TitleBest ResponseYou've already chosen the best response.1
thanks for the help.
 2 years ago
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