janessia
Find x. Round to the nearest tenth.
Picture attached!!



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janessia
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tkhunny
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Have you considered the Law of Sines?

janessia
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no i havent but isnt that opposite hypotenuse?

janessia
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@tkhunny

ChmE
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\[\frac{ a }{ \sin A }=\frac{ b }{ \sin B }=\frac{ c }{ \sin C }\]where a,b,c are sides and A,B,C are the angles opposite the corresponding sides

ChmE
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\[\frac{ x }{ \sin 87 }=\frac{ 21 }{ \sin 37 }\]

tkhunny
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You don't have any right angles. "hypotenuse" doesn't mean anything for this triangle.

ChmE
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cross multiply and solve for x using algebra

janessia
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ohk

ChmE
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when you don't have a right triangle think law of sines or law of cosines

janessia
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ohk so i get rid of the 37 first right?.... by multiplying?

tkhunny
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You calculate the values for sine and then you solve for the missing item. In this case, it is only a simple multiplication.

janessia
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i multiply 21 and 87?

janessia
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which is 1827

tkhunny
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No, there is not 87 or 37. You must first calculate the sine of those angle measures.

janessia
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uggh this is too much and its late thanks for all you help but i cnt concentrate when im sleepy... so i will be asking this question again tomorrow.