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janessia

Find x. Round to the nearest tenth. Picture attached!!

  • one year ago
  • one year ago

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  1. janessia
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    • one year ago
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  2. tkhunny
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    Have you considered the Law of Sines?

    • one year ago
  3. janessia
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    no i havent but isnt that opposite hypotenuse?

    • one year ago
  4. janessia
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    @tkhunny

    • one year ago
  5. ChmE
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    \[\frac{ a }{ \sin A }=\frac{ b }{ \sin B }=\frac{ c }{ \sin C }\]where a,b,c are sides and A,B,C are the angles opposite the corresponding sides

    • one year ago
  6. ChmE
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    \[\frac{ x }{ \sin 87 }=\frac{ 21 }{ \sin 37 }\]

    • one year ago
  7. tkhunny
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    You don't have any right angles. "hypotenuse" doesn't mean anything for this triangle.

    • one year ago
  8. ChmE
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    cross multiply and solve for x using algebra

    • one year ago
  9. janessia
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    ohk

    • one year ago
  10. ChmE
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    when you don't have a right triangle think law of sines or law of cosines

    • one year ago
  11. janessia
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    ohk so i get rid of the 37 first right?.... by multiplying?

    • one year ago
  12. tkhunny
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    You calculate the values for sine and then you solve for the missing item. In this case, it is only a simple multiplication.

    • one year ago
  13. janessia
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    i multiply 21 and 87?

    • one year ago
  14. janessia
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    which is 1827

    • one year ago
  15. tkhunny
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    No, there is not 87 or 37. You must first calculate the sine of those angle measures.

    • one year ago
  16. janessia
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    uggh this is too much and its late thanks for all you help but i cnt concentrate when im sleepy... so i will be asking this question again tomorrow.

    • one year ago
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