## janessia 3 years ago Find x. Round to the nearest tenth. Picture attached!!

1. janessia

2. tkhunny

Have you considered the Law of Sines?

3. janessia

no i havent but isnt that opposite hypotenuse?

4. janessia

@tkhunny

5. ChmE

$\frac{ a }{ \sin A }=\frac{ b }{ \sin B }=\frac{ c }{ \sin C }$where a,b,c are sides and A,B,C are the angles opposite the corresponding sides

6. ChmE

$\frac{ x }{ \sin 87 }=\frac{ 21 }{ \sin 37 }$

7. tkhunny

You don't have any right angles. "hypotenuse" doesn't mean anything for this triangle.

8. ChmE

cross multiply and solve for x using algebra

9. janessia

ohk

10. ChmE

when you don't have a right triangle think law of sines or law of cosines

11. janessia

ohk so i get rid of the 37 first right?.... by multiplying?

12. tkhunny

You calculate the values for sine and then you solve for the missing item. In this case, it is only a simple multiplication.

13. janessia

i multiply 21 and 87?

14. janessia

which is 1827

15. tkhunny

No, there is not 87 or 37. You must first calculate the sine of those angle measures.

16. janessia

uggh this is too much and its late thanks for all you help but i cnt concentrate when im sleepy... so i will be asking this question again tomorrow.