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janessia
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Find x. Round to the nearest tenth.
Picture attached!!
 one year ago
 one year ago
janessia Group Title
Find x. Round to the nearest tenth. Picture attached!!
 one year ago
 one year ago

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tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Have you considered the Law of Sines?
 one year ago

janessia Group TitleBest ResponseYou've already chosen the best response.0
no i havent but isnt that opposite hypotenuse?
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ a }{ \sin A }=\frac{ b }{ \sin B }=\frac{ c }{ \sin C }\]where a,b,c are sides and A,B,C are the angles opposite the corresponding sides
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ \sin 87 }=\frac{ 21 }{ \sin 37 }\]
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
You don't have any right angles. "hypotenuse" doesn't mean anything for this triangle.
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
cross multiply and solve for x using algebra
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
when you don't have a right triangle think law of sines or law of cosines
 one year ago

janessia Group TitleBest ResponseYou've already chosen the best response.0
ohk so i get rid of the 37 first right?.... by multiplying?
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
You calculate the values for sine and then you solve for the missing item. In this case, it is only a simple multiplication.
 one year ago

janessia Group TitleBest ResponseYou've already chosen the best response.0
i multiply 21 and 87?
 one year ago

janessia Group TitleBest ResponseYou've already chosen the best response.0
which is 1827
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
No, there is not 87 or 37. You must first calculate the sine of those angle measures.
 one year ago

janessia Group TitleBest ResponseYou've already chosen the best response.0
uggh this is too much and its late thanks for all you help but i cnt concentrate when im sleepy... so i will be asking this question again tomorrow.
 one year ago
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