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Someone please check.
q+122(q22)>0
q+10q220>0
11q(220+220)>0
11q>220
q>20
 one year ago
 one year ago
Someone please check. q+122(q22)>0 q+10q220>0 11q(220+220)>0 11q>220 q>20
 one year ago
 one year ago

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NickRBest ResponseYou've already chosen the best response.0
where do you get 10q from?
 one year ago

cbmBest ResponseYou've already chosen the best response.0
122, then I distributed by parenthesis
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
you need to distribute first
 one year ago

theEricBest ResponseYou've already chosen the best response.0
That's the start, right?
 one year ago

theEricBest ResponseYou've already chosen the best response.0
@cbm (just making a notification pop up :P )
 one year ago

jayz657Best ResponseYou've already chosen the best response.1
i think you made a mistake there q+122(q22)>0 q+122q+44 >0 q +56 >0 q > 56 q>56
 one year ago

theEricBest ResponseYou've already chosen the best response.0
I agree with jayz657's work. Any questions, @cbm ?
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Thank ya'll so much! I was reworking it. Yep, once I distributed I got the same answer. The sign at the end changed right? From > to <
 one year ago

cbmBest ResponseYou've already chosen the best response.0
I wish you could give more than one best response
 one year ago

theEricBest ResponseYou've already chosen the best response.0
Yep! Because you multiplied or divided by a negative!
 one year ago

theEricBest ResponseYou've already chosen the best response.0
My pleasure. I'm glad you got it worked out :) Good luck with any more you have to do!
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Thanks, I'm struggling with one more now trying to set up an inequality.
 one year ago

theEricBest ResponseYou've already chosen the best response.0
You can ask it here or in another question. I have time if you'd like a hand. Algebra like this can be hard at first.
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Ok, it will take me a minute to type it. Thanks for your help. Yes, I'm too old to learn this stuff.
 one year ago

theEricBest ResponseYou've already chosen the best response.0
Haha, no such thing. It might just require some thinking and rethinking, right? Maybe thinking in a different light! I started thinking about counting cookies/blocks again before so the numbers meant something.
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Your making a rectangular patio that is 10ft wide and 20ft long, using square pavers that have an area of 0.81 sq ft, what is the # of pavers u will need? Write and solve an inequality to find the answer.
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Lol, I'm trying. I thought I had equations but not the fractions
 one year ago

cbmBest ResponseYou've already chosen the best response.0
would it be like (10x20).81=p
 one year ago

theEricBest ResponseYou've already chosen the best response.0
The first step is always understanding the problem. Then we move on.. So I have a quick question... Each "paver" is .81 square feet, and we need to know how many of the will fit in our 10 foot by 20 foot area?
 one year ago

theEricBest ResponseYou've already chosen the best response.0
Alright! Then (10*20) is definately your area of the patio. And you wanna see how many .81 area portions will fit into that. How many times does .81 go into (10*20) is the question to get you to your answer. That's a division thing.
 one year ago

theEricBest ResponseYou've already chosen the best response.0
That's just one way to look at it. There's another way in which you build the equation and solve.. I got the same number after rounding. Is this supposed to be inequality?
 one year ago

cbmBest ResponseYou've already chosen the best response.0
I'm not sure if I'm writing the inequality right or not (10ftx20ft)/.81=p
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Yes, it's supposed to be an inequality
 one year ago

theEricBest ResponseYou've already chosen the best response.0
That's what I would do to!
 one year ago

cbmBest ResponseYou've already chosen the best response.0
To me it works and gives the answer when you work it.
 one year ago

theEricBest ResponseYou've already chosen the best response.0
I don't see why it would be inequality! There must be something I'm not thinking of.. I thought it would want an exact number...You want so many pavers.... OR! Do you want at least so many pavers? Meaning that many or more?
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Do you want me to create a problem so I can give you a medal? I'm not sure what the medal do.
 one year ago

cbmBest ResponseYou've already chosen the best response.0
I was trying to figure out why it want come out to a whole number also unless it's ≥
 one year ago

theEricBest ResponseYou've already chosen the best response.0
They're just sort of recognition you can count. I'm not worried about it. Thanks though!
 one year ago

theEricBest ResponseYou've already chosen the best response.0
Yeah, I think maybe that's the idea of it.. why they want inequality.. Although you'd think rounding it up to 247 would be good enough! Maybe the question was just not appropriate for this subject!
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Oh, ok thanks! Maybe (10x20)/.81≥p
 one year ago

theEricBest ResponseYou've already chosen the best response.0
I would say \[p\ge 246.0\]
 one year ago

theEricBest ResponseYou've already chosen the best response.0
You would want more pavers rather than less. At least you get your patio done that way :P
 one year ago

theEricBest ResponseYou've already chosen the best response.0
Pavers area things should be greater than or equal to the patio area... to get the patio done :P Yeah!
 one year ago

theEricBest ResponseYou've already chosen the best response.0
Using just that sentence, you can set up the inequality. \[p_{NumberOfPavers}\ge A_{PatioArea}\]
 one year ago

cbmBest ResponseYou've already chosen the best response.0
I've been trying everything to get an even number. I don't understand why it would be a decimal. I tried breaking it up into inches, etc. Thanks again for your help.
 one year ago

theEricBest ResponseYou've already chosen the best response.0
It might just not come out to be an even number. It happens. We could solve it to be a fraction instead of a decimal. With fractions, your always exact (no rounding).
 one year ago

theEricBest ResponseYou've already chosen the best response.0
I have five cookies to share between us. How many can we each have? 2.5. Books don't always make problems come out to nice numbers either..
 one year ago

theEricBest ResponseYou've already chosen the best response.0
So maybe that's the case here.
 one year ago

theEricBest ResponseYou've already chosen the best response.0
Same. Good luck with that! If you solve it as a fraction, note that .81 = 81/100.
 one year ago

theEricBest ResponseYou've already chosen the best response.0
\[\frac{10*20}{.81}=\frac{10*20}{\frac{81}{100}}\] Np!
 one year ago

theEricBest ResponseYou've already chosen the best response.0
Just in case... From there, it's \[\frac{10*20*100}{81}=\frac{20000}{81}=246\frac{74}{81}\]
 one year ago

cbmBest ResponseYou've already chosen the best response.0
Yep, that works good or at least it looks better. I figured I could write the equation as (p)x0.81≥200. I'm still working it to see if it will work.
 one year ago

theEricBest ResponseYou've already chosen the best response.0
That's great, and it was the other way I would think of the equation to solve!
 one year ago

theEricBest ResponseYou've already chosen the best response.0
And you don't have to change the sign because 0.81 is not negative.dw:1351404148861:dw
 one year ago

theEricBest ResponseYou've already chosen the best response.0
All other operations keep the inequality the same direction. Adding (positive number) to both sides: Each side gets the same bump up Subtracting (positive number) from bothe sides: Each side gets the same cut down Multiplying (number greater than 1) to both sides: Each side gets larger proportional to its size Dividing both sides by (number greater than one): Each side gets smaller proportional to its size
 one year ago

theEricBest ResponseYou've already chosen the best response.0
I threw in number specifications, just because adding a negative is like subtracting a positve. Then each side gets cut down the same. Same for multiplication/division. Multiplying by a fraction less than one is like dividing by that fraction's reciprocal\[x*\frac{1}{2}=x\div 2\]and so each side gets proportionally smaller. Just some extra, if you wanna think about it. Take care! It was nice working with you!
 one year ago
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