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latremese40

  • 3 years ago

y=logx If y=10, then what is x?

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  1. ParthKohli
    • 3 years ago
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    log base = ?

  2. latremese40
    • 3 years ago
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    it just say x

  3. hartnn
    • 3 years ago
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    10=log x can u convert this in exponential form?

  4. ParthKohli
    • 3 years ago
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    Okay, so what do you get in the equation when you plug \(\rm y = 10\)?

  5. latremese40
    • 3 years ago
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    yes @hartnn

  6. etemplin
    • 3 years ago
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    10 = log x x = 10^10 you raise both powers to whatever the base of the log is to get rid of the log

  7. hartnn
    • 3 years ago
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    what u get?

  8. latremese40
    • 3 years ago
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    so then it will be one?

  9. ParthKohli
    • 3 years ago
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    People, why don't you just help her?

  10. ParthKohli
    • 3 years ago
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    @latremese40 Yes!

  11. hartnn
    • 3 years ago
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    no

  12. etemplin
    • 3 years ago
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    no, x does not equal 1

  13. latremese40
    • 3 years ago
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    thank you @Parthkohli

  14. ParthKohli
    • 3 years ago
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    Whenever you have such a form, then I prefer the exponential form.

  15. etemplin
    • 3 years ago
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    @ParthKohli if x and y were reversed, this would be true

  16. hartnn
    • 3 years ago
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    its not 1

  17. ParthKohli
    • 3 years ago
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    @latremese40 You're welcome :)

  18. etemplin
    • 3 years ago
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    x = 10^10

  19. latremese40
    • 3 years ago
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    how @hartnn

  20. ParthKohli
    • 3 years ago
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    @latremese40 Let me show you.

  21. etemplin
    • 3 years ago
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    if you do log(1) you dont get 10

  22. ParthKohli
    • 3 years ago
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    \[\rm 10 = \log (x)\]Right? But here, the base is 10.

  23. latremese40
    • 3 years ago
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    oka Parthkohli

  24. etemplin
    • 3 years ago
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    so raise both sides to the 10th power to get rid of the log with base 10

  25. ParthKohli
    • 3 years ago
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    \[\rm 10 = \log_{10}(x)\]Do you know what the exponential form is?

  26. hartnn
    • 3 years ago
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    the exponential form \(\huge if, a=log x\implies x=10^a \)

  27. hartnn
    • 3 years ago
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    so what will be 10=log x ?

  28. latremese40
    • 3 years ago
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    but its y=logx then you get 10^x x=1 right?

  29. ParthKohli
    • 3 years ago
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    @latremese40 Let's do something clever.

  30. hartnn
    • 3 years ago
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    when y=10, u get 10=log x

  31. ParthKohli
    • 3 years ago
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    Let's first solve for \(\rm x\).

  32. etemplin
    • 3 years ago
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    @ParthKohli if you plug in 1 for x you dont get 10

  33. hartnn
    • 3 years ago
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    and u get x=10^y

  34. latremese40
    • 3 years ago
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    how bout @parthkohli inbx me cuz im getin confused

  35. ParthKohli
    • 3 years ago
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    \[\rm y = \log_{10}x \]So,\[\rm 10^y = x\]Right?

  36. ParthKohli
    • 3 years ago
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    Now if you have y = 10, then you have\[\rm 10^{10} =x \]Got my point?

  37. latremese40
    • 3 years ago
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    yes i do

  38. ParthKohli
    • 3 years ago
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    And that's your answer! If you prefer the numeric notation, then add ten zeroes in front of 1.

  39. hartnn
    • 3 years ago
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    sorry for the confusion.

  40. latremese40
    • 3 years ago
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    oka... its cool hartnn

  41. etemplin
    • 3 years ago
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    im still confused...how is x=1 like you said earlier?

  42. ParthKohli
    • 3 years ago
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    @etemplin: That answer was out of confusion, so don't mind it. :)

  43. etemplin
    • 3 years ago
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    wow that makes sense now. so x = 10^10 right? just making sure

  44. ChmE
    • 3 years ago
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    |dw:1351402472779:dw|

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