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JusaquikieBest ResponseYou've already chosen the best response.1
\[f(x) = x^2e^{x}\] \[f'(x) =e^{x}(2xx^2)\] \[f'' =e^{x}(x2)^2\] or \[f'' =e^{x}(x^24x+2)\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(f'' =e^{x}(x^24x+2)\) is correct \(f'' =e^{x}(x2)^2\) is incorrect
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
for my infliction points i need f"=0 i thought this should be at 2 but that is not right. when i solve f" for x on my calculator i get \[(\sqrt{2}2) \]and \[\sqrt{2}+2 \]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
x^24x+2 will get u to correct points
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
i believe this has something to do with it being squared but i don't understand why beacuse 0 squared is still 0
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
i know the answer is the first of the infliction points i have listed but i just don't see how to solve the second derivitive that way
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
well how to solve f"=0 that way
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
what exactly is your doubt ? u got \(f'' =e^{x}(x^24x+2)\) now f''(x)=0 will give \((x^24x+2)=0\) can u solve this quadratic to get 2 values of x ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
those 2 values of x will be your inflection points.
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
do i need to use the quadratic formula? beacuse it simplifies to (x2)(x2) so 2 will make it zero
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
@Jusaquikie plz observe that \(f'' =e^{x}(x2)^2\) IS INCORRECT !
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
and you use quadratic formula for \(x^24x+2=0\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
or u could complete the square
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
ok i see now that for (x2) to work it would have to be X^2  4x +4
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
it's just late and my mind is jumping to the easiest answer after computing that beastly second derivatives.
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
so the quadratic formula would be what i'd use if they didn't come out even and if i used that i bet i'd get the right answer
 one year ago

JusaquikieBest ResponseYou've already chosen the best response.1
thanks for the help @hartnn
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
good night and sweet dreams :)
 one year ago
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