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Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1\[f(x) = x^2e^{x}\] \[f'(x) =e^{x}(2xx^2)\] \[f'' =e^{x}(x2)^2\] or \[f'' =e^{x}(x^24x+2)\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(f'' =e^{x}(x^24x+2)\) is correct \(f'' =e^{x}(x2)^2\) is incorrect

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1for my infliction points i need f"=0 i thought this should be at 2 but that is not right. when i solve f" for x on my calculator i get \[(\sqrt{2}2) \]and \[\sqrt{2}+2 \]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1x^24x+2 will get u to correct points

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1i believe this has something to do with it being squared but i don't understand why beacuse 0 squared is still 0

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1i know the answer is the first of the infliction points i have listed but i just don't see how to solve the second derivitive that way

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1well how to solve f"=0 that way

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1what exactly is your doubt ? u got \(f'' =e^{x}(x^24x+2)\) now f''(x)=0 will give \((x^24x+2)=0\) can u solve this quadratic to get 2 values of x ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1those 2 values of x will be your inflection points.

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1do i need to use the quadratic formula? beacuse it simplifies to (x2)(x2) so 2 will make it zero

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1@Jusaquikie plz observe that \(f'' =e^{x}(x2)^2\) IS INCORRECT !

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1and you use quadratic formula for \(x^24x+2=0\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1or u could complete the square

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1ok i see now that for (x2) to work it would have to be X^2  4x +4

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1it's just late and my mind is jumping to the easiest answer after computing that beastly second derivatives.

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1so the quadratic formula would be what i'd use if they didn't come out even and if i used that i bet i'd get the right answer

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.1thanks for the help @hartnn

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1good night and sweet dreams :)
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