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Jusaquikie
Group Title
trying to find an infliction point. the rest i'll make neat.
 2 years ago
 2 years ago
Jusaquikie Group Title
trying to find an infliction point. the rest i'll make neat.
 2 years ago
 2 years ago

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Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
\[f(x) = x^2e^{x}\] \[f'(x) =e^{x}(2xx^2)\] \[f'' =e^{x}(x2)^2\] or \[f'' =e^{x}(x^24x+2)\]
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(f'' =e^{x}(x^24x+2)\) is correct \(f'' =e^{x}(x2)^2\) is incorrect
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
for my infliction points i need f"=0 i thought this should be at 2 but that is not right. when i solve f" for x on my calculator i get \[(\sqrt{2}2) \]and \[\sqrt{2}+2 \]
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
x^24x+2 will get u to correct points
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
i believe this has something to do with it being squared but i don't understand why beacuse 0 squared is still 0
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
i know the answer is the first of the infliction points i have listed but i just don't see how to solve the second derivitive that way
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
well how to solve f"=0 that way
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what exactly is your doubt ? u got \(f'' =e^{x}(x^24x+2)\) now f''(x)=0 will give \((x^24x+2)=0\) can u solve this quadratic to get 2 values of x ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
those 2 values of x will be your inflection points.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
do i need to use the quadratic formula? beacuse it simplifies to (x2)(x2) so 2 will make it zero
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
@Jusaquikie plz observe that \(f'' =e^{x}(x2)^2\) IS INCORRECT !
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
and you use quadratic formula for \(x^24x+2=0\)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
or u could complete the square
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
ok i see now that for (x2) to work it would have to be X^2  4x +4
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
it's just late and my mind is jumping to the easiest answer after computing that beastly second derivatives.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
so the quadratic formula would be what i'd use if they didn't come out even and if i used that i bet i'd get the right answer
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
thanks for the help @hartnn
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
thats correct.
 2 years ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.1
now i can sleep
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
good night and sweet dreams :)
 2 years ago
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