Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
soccergal12
Group Title
Researchers studying photoperiodism use the wingspanlebur as an experimental plant. The variable of interest, X, the number of hours of uninterrupted darkness required to produce flowering is normally distributed with a mean of 14.5 hours and standard deviation 1.0 hours.
c. What is the probability that out of a random sample of 20 wingspanleburs less than two require between 12 and 15 hours of uninterrupted darkness to produce flowering?
I got this far:
Let Y=# wingspanleburs requiring between 12 and 15 hours of uninterrupted darkness (out of 20)
Y~BIN(n=20, p=0.6853)
P(Y<2) = ?
But I'm unsure about how to use P(Y<2) to get the answer 4.0 x 10^ 9
 2 years ago
 2 years ago
soccergal12 Group Title
Researchers studying photoperiodism use the wingspanlebur as an experimental plant. The variable of interest, X, the number of hours of uninterrupted darkness required to produce flowering is normally distributed with a mean of 14.5 hours and standard deviation 1.0 hours. c. What is the probability that out of a random sample of 20 wingspanleburs less than two require between 12 and 15 hours of uninterrupted darkness to produce flowering? I got this far: Let Y=# wingspanleburs requiring between 12 and 15 hours of uninterrupted darkness (out of 20) Y~BIN(n=20, p=0.6853) P(Y<2) = ? But I'm unsure about how to use P(Y<2) to get the answer 4.0 x 10^ 9
 2 years ago
 2 years ago

This Question is Closed

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
The probability that the hours of darkness required to produce flowering lies between 12 and 15 hours is 0.6853. The probability that only one out of a random sample of 20 requires between 12 and 15 hours of darkness to produce flowering is found from the binomial distribution as follows: \[P(1from20)=\left(\begin{matrix}20 \\ 1\end{matrix}\right)\times 0.6853(10.6853)^{19}=3.95\times 10^{9}\] If you now use the binomial distribution to find the probability that zero out of a random sample of 20 requires between 12 and 15 hours of darkness to produce flowering and add this probability to the one calculated above you will have the solution.
 2 years ago

soccergal12 Group TitleBest ResponseYou've already chosen the best response.0
thank you
 2 years ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.1
You're welcome :)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.