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bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.4Is it: (1/e^2)*(Cos1 + iSin1) ?

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.4a complex number in form: z = r*e^(i*theta) = r(Cos(theta)+iSin(theta))

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.1\( e^{i\theta} = Cos\theta + iSin\theta\) Ya thats what i Have seen around so I am assuming ur answer is correct

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.4I guess.. it's just that I thought it would look somewhat neater

bahrom7893
 2 years ago
Best ResponseYou've already chosen the best response.4well thanks everyone

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1start with \[e^{2}e^i\] then oh, you get what you wrote

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1since \(e^{ix}=\cos(x)+i\sin(x)\)

kc_kennylau
 8 months ago
Best ResponseYou've already chosen the best response.0I've recently dealt with this kinda things before... let me think...

kc_kennylau
 8 months ago
Best ResponseYou've already chosen the best response.0Wait oh satellite has already solved the problem, a=0 and b=\(\large e^{2}\)
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