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bahrom7893 Group TitleBest ResponseYou've already chosen the best response.4
Is it: (1/e^2)*(Cos1 + iSin1) ?
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.4
@satellite73
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.4
a complex number in form: z = r*e^(i*theta) = r(Cos(theta)+iSin(theta))
 one year ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.1
\( e^{i\theta} = Cos\theta + iSin\theta\) Ya thats what i Have seen around so I am assuming ur answer is correct
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.4
I guess.. it's just that I thought it would look somewhat neater
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.4
well thanks everyone
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.4
back to studying..
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
start with \[e^{2}e^i\] then oh, you get what you wrote
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
since \(e^{ix}=\cos(x)+i\sin(x)\)
 one year ago

kc_kennylau Group TitleBest ResponseYou've already chosen the best response.0
I've recently dealt with this kinda things before... let me think...
 5 months ago

kc_kennylau Group TitleBest ResponseYou've already chosen the best response.0
Wait oh satellite has already solved the problem, a=0 and b=\(\large e^{2}\)
 5 months ago
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