Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

3psilon

  • 3 years ago

The angular acceleration α for some particle moving in a circle depends linearly on its angular velocity ω. α = A ω where A is some constant. The initial angular velocity is ω0. The initial angular position is ω0/A. What is θ(t)?

  • This Question is Closed
  1. gerryliyana
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    θ(t) = ωo t + 1/2 α t^2

  2. Algebraic!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\theta (t) = \frac{ \omega _{0} }{ A } +\omega _{0} t +\frac{ 1 }{ 2 } A \omega _{0}t^2\]

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy