Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
jonnymiller
Group Title
How do I find the indefinite integral of sin(x)/x ?
 one year ago
 one year ago
jonnymiller Group Title
How do I find the indefinite integral of sin(x)/x ?
 one year ago
 one year ago

This Question is Closed

ahmedelmorsi Group TitleBest ResponseYou've already chosen the best response.0
by parts
 one year ago

ahmedelmorsi Group TitleBest ResponseYou've already chosen the best response.0
its equal x*cos(x)cos(x)
 one year ago

guepardo14 Group TitleBest ResponseYou've already chosen the best response.0
Integral [ (sin(x)/x) dx ] The fact of the matter is, this integral is one that cannot be expressed in terms of elementary functions. There's no way we can solve this using the methods we know; we cannot use integration by parts, partial fractions, substitution, trigonometric substitution, etc to solve this. We can, however, approximate the integral through a power series. sin(x) has its own power series, so all we need to do is divide each term of the series by x (this represents (1/x)sin(x), or sin(x)/x) and then integrate thereafter. como: Your proposed solution doesn't work, and here's why. Let f(x) = (1/x)cos x  (1/x²)sinx + C To make it easier to differentiate, factor (1/x). f(x) = (1/x) [cos(x)  (1/x)sin(x)] + C Differentiate using the product rule, noting that d/dx (1/x) = 1/x^2 gives us f'(x) = (1/x^2) [cos(x)  (1/x)sin(x)] + (1/x) [sin(x)  [(1/x^2)sin(x) + (1/x)cos(x)] ] f'(x) = cos(x)/x^2 + sin(x)/x^3  sin(x)/x + sin(x)/x^2  cos(x)/x And as you can see, it looks nothing like sin(x)/x.
 one year ago

ahmedelmorsi Group TitleBest ResponseYou've already chosen the best response.0
why we cant solve it by parts ???????????
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.