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diamondeye10 Group Title

the product of two consecutive positive even numbers is 1520. What are the numbers? when I try "n" and "n+2" i get an odd number

  • 2 years ago
  • 2 years ago

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  1. JakeV8 Group Title
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    you can express those consecutive even numbers like "n" and "n+2" and their product is (n)(n+2) = 1520

    • 2 years ago
  2. satellite73 Group Title
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    guess and check for this one there is no other way

    • 2 years ago
  3. satellite73 Group Title
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    \(40\times 42=1680\) nope, too big. try again with smaller numbers

    • 2 years ago
  4. JakeV8 Group Title
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    That's not quite the right equation...

    • 2 years ago
  5. satellite73 Group Title
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    @Albert0898 it is the PRODUCT not the sum

    • 2 years ago
  6. satellite73 Group Title
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    you cannot use an equation to solve this, only to rewrite the question, don't be fooled you just have to grind it until you find it

    • 2 years ago
  7. bahrom7893 Group Title
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    38 and 40

    • 2 years ago
  8. bahrom7893 Group Title
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    satellite was close ;)

    • 2 years ago
  9. bahrom7893 Group Title
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    hahah, sorry i used your guess to approximate.

    • 2 years ago
  10. satellite73 Group Title
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    yeah a calculator helps i started too high, went down a couple, got it in try two

    • 2 years ago
  11. JakeV8 Group Title
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    n(n+2) = 1520 n^2 + 2n - 1520 = 0 (n-38)(n+40) = 0 Since the numbers are positive, the 2nd solution doesn't work. n must be 38 and n + 2 is 40.

    • 2 years ago
  12. JakeV8 Group Title
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    (I couldn't factor that as easily as I made it sound... so a calculator helped me too :) )

    • 2 years ago
  13. tcarroll010 Group Title
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    You definitely do not have to grind it out and guess. But the equation is not shown correctly above. It is (2N)(2N + 2) = 1520. Becomes a simple quadratic. Solve for N. Answer will be the 2N and 2N + 2.

    • 2 years ago
  14. satellite73 Group Title
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    so my question is, how did you know how to factor ? you had to come up with two numbers whose product is 1520 and that are two apart in other words just rewrote the question, still had to guess and check

    • 2 years ago
  15. Albert0898 Group Title
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    x = even number x + 2 = consecutive even number x + 2 * x = 1520 x + 2 = 1520/x x = 1518/x x * x = 1518 Find the square root of 1518. Approximate and Closest Even Number: 38. x = 38 x + 2 = 40

    • 2 years ago
  16. satellite73 Group Title
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    i guess if you wanted to be ridiculous you could write \[x^2+2x=1520\] and complete the square \[(x+1)^2=1521\] \[x+1=\sqrt{1521}=39\]\[x=38\] but that is a silly thing to do

    • 2 years ago
  17. JakeV8 Group Title
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    @satellite73 Yes, I agree with you... that's what I meant... you either guess and check to factor, or just guess and check vs. 1520. My only point was that it is possible to write an equation to solve something like this.

    • 2 years ago
  18. satellite73 Group Title
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    @JakeV8 yes you are right, but i maintain that changing a problem like this in to an equation and then solving it by solving the original problem in words is a dog chasing its tail

    • 2 years ago
  19. tcarroll010 Group Title
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    You guys are missing it all together. Set the variables as 2N and 2N + 2. If you set N to a positive integer, 2N and 2N + 2 are automatically even. Becomes a simple quadratic. See my previous post.

    • 2 years ago
  20. diamondeye10 Group Title
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    thanks all I think I found my problem

    • 2 years ago
  21. tcarroll010 Group Title
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    Ok, I'm here. Give me a second to refresh myself on this.

    • 2 years ago
  22. tcarroll010 Group Title
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    Ok, I'm up to speed. I still stand firmly on my answer methodology. The way to GUARANTEE that you have two even numbers is to use (2N)(2N + 2) = 1520 because 2N and 2N + 2 will be FORCED to be even if N is a positive integer. Absolutely. I strongly suggest you use this methodology. If I understand, your current question has something to do with 3 positive even numbers now? Is that correct?

    • 2 years ago
  23. tcarroll010 Group Title
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    And please, whatever you do, don't follow satellite73 on this problem. He is WAY off base suggesting that you guess. That's beyond ludicrous.

    • 2 years ago
  24. diamondeye10 Group Title
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    @tcarroll010, that is the equation I was using however, i am still unable to find two positive even numbers. No I do not have to find three evennumbers, I was seeing if the way I was working it would give even numbers for three. hope that makes sence, sorry my computer is slow. . I only need two positive even numbers

    • 2 years ago
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