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diamondeye10
Group Title
the product of two consecutive positive even numbers is 1520. What are the numbers? when I try "n" and "n+2" i get an odd number
 2 years ago
 2 years ago
diamondeye10 Group Title
the product of two consecutive positive even numbers is 1520. What are the numbers? when I try "n" and "n+2" i get an odd number
 2 years ago
 2 years ago

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JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
you can express those consecutive even numbers like "n" and "n+2" and their product is (n)(n+2) = 1520
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
guess and check for this one there is no other way
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\(40\times 42=1680\) nope, too big. try again with smaller numbers
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
That's not quite the right equation...
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
@Albert0898 it is the PRODUCT not the sum
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
you cannot use an equation to solve this, only to rewrite the question, don't be fooled you just have to grind it until you find it
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
38 and 40
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
satellite was close ;)
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
hahah, sorry i used your guess to approximate.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yeah a calculator helps i started too high, went down a couple, got it in try two
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
n(n+2) = 1520 n^2 + 2n  1520 = 0 (n38)(n+40) = 0 Since the numbers are positive, the 2nd solution doesn't work. n must be 38 and n + 2 is 40.
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
(I couldn't factor that as easily as I made it sound... so a calculator helped me too :) )
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
You definitely do not have to grind it out and guess. But the equation is not shown correctly above. It is (2N)(2N + 2) = 1520. Becomes a simple quadratic. Solve for N. Answer will be the 2N and 2N + 2.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
so my question is, how did you know how to factor ? you had to come up with two numbers whose product is 1520 and that are two apart in other words just rewrote the question, still had to guess and check
 2 years ago

Albert0898 Group TitleBest ResponseYou've already chosen the best response.0
x = even number x + 2 = consecutive even number x + 2 * x = 1520 x + 2 = 1520/x x = 1518/x x * x = 1518 Find the square root of 1518. Approximate and Closest Even Number: 38. x = 38 x + 2 = 40
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
i guess if you wanted to be ridiculous you could write \[x^2+2x=1520\] and complete the square \[(x+1)^2=1521\] \[x+1=\sqrt{1521}=39\]\[x=38\] but that is a silly thing to do
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 Yes, I agree with you... that's what I meant... you either guess and check to factor, or just guess and check vs. 1520. My only point was that it is possible to write an equation to solve something like this.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
@JakeV8 yes you are right, but i maintain that changing a problem like this in to an equation and then solving it by solving the original problem in words is a dog chasing its tail
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
You guys are missing it all together. Set the variables as 2N and 2N + 2. If you set N to a positive integer, 2N and 2N + 2 are automatically even. Becomes a simple quadratic. See my previous post.
 2 years ago

diamondeye10 Group TitleBest ResponseYou've already chosen the best response.0
thanks all I think I found my problem
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
Ok, I'm here. Give me a second to refresh myself on this.
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
Ok, I'm up to speed. I still stand firmly on my answer methodology. The way to GUARANTEE that you have two even numbers is to use (2N)(2N + 2) = 1520 because 2N and 2N + 2 will be FORCED to be even if N is a positive integer. Absolutely. I strongly suggest you use this methodology. If I understand, your current question has something to do with 3 positive even numbers now? Is that correct?
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
And please, whatever you do, don't follow satellite73 on this problem. He is WAY off base suggesting that you guess. That's beyond ludicrous.
 2 years ago

diamondeye10 Group TitleBest ResponseYou've already chosen the best response.0
@tcarroll010, that is the equation I was using however, i am still unable to find two positive even numbers. No I do not have to find three evennumbers, I was seeing if the way I was working it would give even numbers for three. hope that makes sence, sorry my computer is slow. . I only need two positive even numbers
 2 years ago
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